A sequence of numbers \(a_1, a_2, a_3,\ldots\) is defined as follows: \(a_1=3, a_2=5,\) and every term in the sequence after \(a_2\) is the product of all terms in the sequence preceding it, e.g, \(a_3=(a_1)(a_2)\) and \(a_4=(a1)(a2)(a3).\) If \(a_n=t\) and \(n>2,\) what is the value of \(a_{n+2}\) in terms of \(t?\)
(A) \(4t\)
(B) \(t^2\)
(C) \(t^3\)
(D) \(t^4\)
(E) \(t^8\)
Answer: D
Source: Official Guide
A sequence of numbers \(a_1, a_2, a_3,\ldots\) is defined as follows: \(a_1=3, a_2=5,\) and every term in the sequence
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Let's list a few terms....VJesus12 wrote: ↑Fri Jan 28, 2022 7:24 amA sequence of numbers \(a_1, a_2, a_3,\ldots\) is defined as follows: \(a_1=3, a_2=5,\) and every term in the sequence after \(a_2\) is the product of all terms in the sequence preceding it, e.g, \(a_3=(a_1)(a_2)\) and \(a_4=(a1)(a2)(a3).\) If \(a_n=t\) and \(n>2,\) what is the value of \(a_{n+2}\) in terms of \(t?\)
(A) \(4t\)
(B) \(t^2\)
(C) \(t^3\)
(D) \(t^4\)
(E) \(t^8\)
Answer: D
Source: Official Guide
term1 = 3
term2 = 5
term3 = (term2)(term1) = (5)(3) = 15 (term2)(term1)
term4 = (term3)(term2)(term1) = (15)(5)(3) = 15²
term5 = (term4)(term3)(term2)(term1) = (15²)(15)(5)(3) = 15⁴
term6 = (term5)(term4)(term3)(term2)(term1) = (15⁴)(15²)(15)(5)(3) = 15⁸
At this point, we can see the pattern.
Continuing, we get....
term7 = 15^16
term8 = 15^32
Each term in the sequence is equal to the SQUARE of term before it
If term_n =t and n > 2, what is the value of term_n+2 in terms of t?
So, term_n = t
term_n+1 = t²
term_n+2 = t⁴
Answer: D
Cheers,
Brent