If \(x\) is positive and \(y\) is \(1\) more than the square of \(x\), then what is the value of \(x\) in terms of \(y\)?
A. \(y^2-1\)
B. \(y^2+1\)
C. \(\sqrt{y}-1\)
D. \(\sqrt{y-1}\)
E. \(\sqrt{y+1}\)
The OA is D
Source: Princeton Review
Algebra
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Solution:
We are given that y = x^2 + 1. Thus:
x^2 = y - 1
x = ±√(y - 1)
However, since x is positive, then x = √(y - 1) only.
Answer: D
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