How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?
A. 50%
B. 87%
C. 100%
D. 187%
E. 200%
OA C
Source: Veritas Prep
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How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring
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BTGmoderatorDC
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Jay@ManhattanReview
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The combined area of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches = 2*17*11 sq inchesBTGmoderatorDC wrote: ↑Mon Jun 29, 2020 5:28 pmHow much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?
A. 50%
B. 87%
C. 100%
D. 187%
E. 200%
OA C
Source: Veritas Prep
The combined area of the front and back of a rectangular sheet of paper measuring 8.5 inches by 17 inches = 2*8.5*11 sq inches
So, the required percentage increase = [(2*17*11 – 2*8.5*11)/(2*8.5*11)]*100% = 100%
Correct answer: C
Hope this helps!
-Jay
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Scott@TargetTestPrep
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Solution:BTGmoderatorDC wrote: ↑Mon Jun 29, 2020 5:28 pmHow much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 17 inches than that of a rectangular sheet of paper measuring 8.5 inches by 11 inches?
A. 50%
B. 87%
C. 100%
D. 187%
E. 200%
OA C
We see that one of the dimensions of the two rectangles is equal while the other dimension of the larger rectangle is twice that of the smaller rectangle. Therefore, the combined area s of the front and back of the larger rectangular sheet is twice that of the smaller rectangular sheet, i.e., 100% greater than that of the smaller rectangular sheet.
Answer: C
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