Let $M$ be the maximum value and $N$ be the minimum value of the expression $\dfrac{x^2+y}{y}$ if $a\le x\le b$

Let $M$ be the maximum value and $N$ be the minimum value of the expression $\dfrac{x^2+y}{y}$ if $a\le x\le b$ and $c\le y\le d,$ then what is the value of $M - N?$

(1) $d = 7$
(2) $a = -2, b = 5$ and $c = 3$

Answer: B

Source: Princeton Review

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