GMATPrep question
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- jayhawk2001
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Darn, this was a toughie...
Is it D ?
Lets assume Fx and Fy = full-time employees in x and y resp
Similarly, Px and Py = part-time employees in x and y resp
We are asked to find if
Fx/Px > (Fx+Fy) / (Px+Py)
i.e.
Fx/Px > Fx/Px [ (1+Fy/Fx) / (1+Py/Px) ]
1 > (1+Fy/Fx) / (1+Py/Px)
1 + Py/Px > 1 + Fy/Fx
Py / Px > Fy/Fx
or
Fx/Px > Fy/Py
1 - sufficient.
Fy/Py > (Fx+Fy) / (Px+Py)
Fy/Py > Fy/Py [ (1+Fx/Fy) / (1+Px/Py) ]
Fy/Py > Fx/Px
So, sufficient.
2 - sufficient.
(Fx+Fy) / (Px+Py)
= Fx/Px [ (1+Fy/Fx) / (1 + Py/Px) ]
We are given Fy/Fx < 1 and Py/Px > 1
So, ratio for Z less than Fx/Px. So, sufficient.
Is it D ?
Lets assume Fx and Fy = full-time employees in x and y resp
Similarly, Px and Py = part-time employees in x and y resp
We are asked to find if
Fx/Px > (Fx+Fy) / (Px+Py)
i.e.
Fx/Px > Fx/Px [ (1+Fy/Fx) / (1+Py/Px) ]
1 > (1+Fy/Fx) / (1+Py/Px)
1 + Py/Px > 1 + Fy/Fx
Py / Px > Fy/Fx
or
Fx/Px > Fy/Py
1 - sufficient.
Fy/Py > (Fx+Fy) / (Px+Py)
Fy/Py > Fy/Py [ (1+Fx/Fy) / (1+Px/Py) ]
Fy/Py > Fx/Px
So, sufficient.
2 - sufficient.
(Fx+Fy) / (Px+Py)
= Fx/Px [ (1+Fy/Fx) / (1 + Py/Px) ]
We are given Fy/Fx < 1 and Py/Px > 1
So, ratio for Z less than Fx/Px. So, sufficient.
- jayhawk2001
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On the real test, I'd vote for choosing numbers too .800GMAT wrote:Thanks jayhawk.......
Since It is a ratio that we are asked to compare, I picked numbers to solve this...
You are right..the answer is D
I was just trying to explain this mathematically using an equation