\(A, B,\) and \(C\) are consecutive odd integers such that \(A < B < C.\) If \(A + B + C = 81,\) then \(A + C =\)
A) 52
B) 54
C) 56
D) 58
E) 60
Answer: B
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\(A, B,\) and \(C\) are consecutive odd integers such that \(A < B < C.\) If \(A + B + C = 81,\) then \(A + C =\)
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Gmat_mission
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Solution:Gmat_mission wrote: ↑Thu Sep 24, 2020 2:33 am\(A, B,\) and \(C\) are consecutive odd integers such that \(A < B < C.\) If \(A + B + C = 81,\) then \(A + C =\)
A) 52
B) 54
C) 56
D) 58
E) 60
Answer: B
Since A, B, and C are consecutive odd integers, which constitute an evenly-spaced set, we see that B must be the average, or 81/3 = 27. Thus, A = 25 and C = 29, and A + C = 25 + 29 = 54.
Answer: B
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