\(\dfrac{2\frac35-1\frac23}{\frac23-\frac35}\)
(A) 16
(B) 14
(C) 3
(D) 1
(E) -1
Answer: B
Source: Official Guide
\(\dfrac{2\frac35-1\frac23}{\frac23-\frac35}\)
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$$\frac{2\frac{3}{5}-1\frac{2}{3}}{\frac{2}{3}-\frac{3}{5}}=\frac{\frac{13}{5}-\frac{5}{3}}{\frac{2}{3}-\frac{3}{5}}$$
$$=\frac{\frac{39-25}{15}}{\frac{10-9}{15}}$$
$$=\frac{\frac{14}{15}}{\frac{1}{15}}$$
$$=\frac{14}{15}\cdot\frac{15}{1}=14$$
Answer = option B
$$=\frac{\frac{39-25}{15}}{\frac{10-9}{15}}$$
$$=\frac{\frac{14}{15}}{\frac{1}{15}}$$
$$=\frac{14}{15}\cdot\frac{15}{1}=14$$
Answer = option B
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Solution:Gmat_mission wrote: ↑Thu Sep 24, 2020 2:24 am\(\dfrac{2\frac35-1\frac23}{\frac23-\frac35}\)
(A) 16
(B) 14
(C) 3
(D) 1
(E) -1
Answer: B
Source: Official Guide
We want to rid both the numerator and denominator of fractions. Multiplying the expression by 15/15, we have:
[(30 + 9) - (15 + 10)] / (10 - 9) = (39 - 25)/1 = 14
Answer: B
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