A plane was originally flying at an altitude of x feet when it ascended 2,000 feet and then descended 5,000 feet. If the plane's altitude after these two changes was 1/3 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet ?
(A) x + 2000 = 1/3*(x - 3000)
(B) 1/3*(x - 3000) = x
(C) x + 3000 = 1/3*x
(D) x - 7000 = 1/3*x
(E) x - 3000 = 1/3*x
OA E
Source: Princeton Review
A plane was originally flying at an altitude of x feet when it ascended 2,000 feet and then descended 5,000 feet. If the
This topic has expert replies
-
- Moderator
- Posts: 7187
- Joined: Thu Sep 07, 2017 4:43 pm
- Followed by:23 members
Last edited by BTGmoderatorDC on Fri Feb 21, 2020 4:37 pm, edited 1 time in total.
GMAT/MBA Expert
- Jay@ManhattanReview
- GMAT Instructor
- Posts: 3008
- Joined: Mon Aug 22, 2016 6:19 am
- Location: Grand Central / New York
- Thanked: 470 times
- Followed by:34 members
The plane's altitude after the first change = x + 2,000;BTGmoderatorDC wrote: ↑Thu Feb 20, 2020 5:45 pmA plane was originally flying at an altitude of x feet when it ascended 2,000 feet and then descended 5,000 feet. If the plane's altitude after these two changes was 1/3 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet ?
(A) x + 2000 = 1/3*(x - 3000)
(B) 1/3*(x - 3000) = x
(C) x + 3000 = 1/3*x
(D) x - 7000 = 1/3*x
(E) x - 3000 = 1/3*x
OA E
Source: Princeton Review
Again, the plane's altitude after the second change = x + 2,000 – 5,000 = x – 3,000;
=> x/3 = x – 3,000
The correct answer: E
Hope this helps!
-Jay
_________________
Manhattan Review
Locations: Manhattan Review Himayatnagar | GMAT Prep Hyderabad | GRE Prep Bangalore | Chennai GRE Coaching | and many more...
Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7223
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
The plane’s original altitude was x. After ascending 2,000 feet and descending 5,000 feet; the altitude of the plane became x + 2000 - 5000 = x - 3000. We are given that this was equal to 1/3 of its original altitude, so x - 3000 must equal 1/3*x. Thus, the equation that gives the plane’s original altitude is x - 3000 = 1/3*x.BTGmoderatorDC wrote: ↑Thu Feb 20, 2020 5:45 pmA plane was originally flying at an altitude of x feet when it ascended 2,000 feet and then descended 5,000 feet. If the plane's altitude after these two changes was 1/3 its original altitude, then the solution of which of the following equations gives the plane's original altitude, in feet ?
(A) x + 2000 = 1/3*(x - 3000)
(B) 1/3*(x - 3000) = x
(C) x + 3000 = 1/3*x
(D) x - 7000 = 1/3*x
(E) x - 3000 = 1/3*x
OA E
Source: Princeton Review
Answer: E
Scott Woodbury-Stewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews