A farmer who owns several farms estimates that orange production on her farms of greater than 500 acres will increase by 30% this year, and orange production on all of her other farms will increase by 10% this year. Last year, orange production on those farms greater than 500 acres was 20,000 kilograms and for all of her other farms it was 8,200. According to the farmer, if all of her farms are operational this year, what will be the total estimated orange production on this year?
A 28,240
B 32,660
C 33,840
D 35,020
E 39,480
Percentage question
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30% estimated increase for farms greater than 500 acres:amontobin wrote:A farmer who owns several farms estimates that orange production on her farms of greater than 500 acres will increase by 30% this year, and orange production on all of her other farms will increase by 10% this year. Last year, orange production on those farms greater than 500 acres was 20,000 kilograms and for all of her other farms it was 8,200. According to the farmer, if all of her farms are operational this year, what will be the total estimated orange production on this year?
A 28,240
B 32,660
C 33,840
D 35,020
E 39,480
20,000 + (30% of 20,000) = 20,000 + 6000 = 26,000.
10% estimated increase for all other farms:
8200 + (10% of 8200) = 8200 + 820 = 9020.
Total estimated production for all of the farms = 26,000 + 9020 = 35,020.
The correct answer is D.
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This one is a typical word problem which has a lot to read yet the problem is very simple.amontobin wrote:A farmer who owns several farms estimates that orange production on her farms of greater than 500 acres will increase by 30% this year, and orange production on all of her other farms will increase by 10% this year. Last year, orange production on those farms greater than 500 acres was 20,000 kilograms and for all of her other farms it was 8,200. According to the farmer, if all of her farms are operational this year, what will be the total estimated orange production on this year?
A 28,240
B 32,660
C 33,840
D 35,020
E 39,480
We have:
Last year,
Total production of greater than 500-acre farms = 20,000 kgs.
Total production of other farms = 8,200 kgs.
This year,
The rate of increase in the yield of greater than 500-acre farms = 30%
The rate of increase in the yield of other farms = 10%
Thus, this year,
Total production of greater than 500-acre farms = 20,000 + 20,000*30% = 26,000 kgs.
Total production of other farms = 8,200 kgs. = 8200 + 8200*10% = 9020 kgs.
Thus, the total production of all the farms = 26,000 + 9020 = 35,020 kgs.
The correct answer: D
Hope this helps!
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Hi amontobin,
As Mitch and Jay have shown, this question is essentially just about doing some basic arithmetic. Depending on how comfortable you are with the concept of Weighted Averages and Estimation, you could answer the question with a different type of math though.
We know the TOTAL orange production was 20,000 + 8,200 = 28,200 kg.
The estimated grown of the larger farms is 30% (the 20,000 kg)
The estimated grown of the larger farms is 10% (the 8,200 kg)
Thus, the total growth will have to be something BETWEEN 10% and 30%. Since 20,000 is so much bigger than 8,200, the weighted average would have to be something closer to 30% (re: measurably higher than 20% overall)
10% of 28,200 = 2820
20% of 28,200 = 5640
30% of 28,200 = 8460
20% overall growth = Adding 5640 to 28,200 gives us 33,840
30% overall growth = Adding 8460 to 28,200 gives us 36,660
We need an answer that's between those two totals... and there's only one that 'fits'..
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
As Mitch and Jay have shown, this question is essentially just about doing some basic arithmetic. Depending on how comfortable you are with the concept of Weighted Averages and Estimation, you could answer the question with a different type of math though.
We know the TOTAL orange production was 20,000 + 8,200 = 28,200 kg.
The estimated grown of the larger farms is 30% (the 20,000 kg)
The estimated grown of the larger farms is 10% (the 8,200 kg)
Thus, the total growth will have to be something BETWEEN 10% and 30%. Since 20,000 is so much bigger than 8,200, the weighted average would have to be something closer to 30% (re: measurably higher than 20% overall)
10% of 28,200 = 2820
20% of 28,200 = 5640
30% of 28,200 = 8460
20% overall growth = Adding 5640 to 28,200 gives us 33,840
30% overall growth = Adding 8460 to 28,200 gives us 36,660
We need an answer that's between those two totals... and there's only one that 'fits'..
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
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Am I the only one who can't see the poll in the header? I see it in the title, but the thread shows as a normal thread, with no poll option or results.
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I can see it, but the configuration is so inexplicably odd, it's hard not to think of election ballots in Florida circa 2000.Matt@VeritasPrep wrote:Am I the only one who can't see the poll in the header? I see it in the title, but the thread shows as a normal thread, with no poll option or results.
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The total estimated orange production his year will be:amontobin wrote: ↑Mon Jul 17, 2017 10:42 amA farmer who owns several farms estimates that orange production on her farms of greater than 500 acres will increase by 30% this year, and orange production on all of her other farms will increase by 10% this year. Last year, orange production on those farms greater than 500 acres was 20,000 kilograms and for all of her other farms it was 8,200. According to the farmer, if all of her farms are operational this year, what will be the total estimated orange production on this year?
A 28,240
B 32,660
C 33,840
D 35,020
E 39,480
20,000 x 1.3 + 8,200 x 1.1 = 26,000 + 9,020 = 35,020
Answer: D
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