Hi,
The answer is A) and hope someone could give me explanation..thax
There are between 100 and 110 cards in a collection of cards. If they are counted out 3 at a time, there are 2 left over, but if they are counted out 4 at a time, there is 1 left over. How many cards are in the collection?
(A) 101
(B) 103
(C) 106
(D) 107
(E) 109
500 ps
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- ajith
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The numbers following the first conidtion in the given range ie remainder of 2 when divided by 3 are 101, 104 and 107
The numbers following the second conidtion in the given range ie remainder of 1 when divided by 4 are 101, 105,109
when you look for the number which follows both the conditions it should be in both the sets , ie the number is 101
There are more complex methods, but this is the easiest for these kind of problems, I will explain one difficult method in the next post.
The numbers following the second conidtion in the given range ie remainder of 1 when divided by 4 are 101, 105,109
when you look for the number which follows both the conditions it should be in both the sets , ie the number is 101
There are more complex methods, but this is the easiest for these kind of problems, I will explain one difficult method in the next post.
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If the cards are counted 3 at a time and 2 are left over. This indictaes that when the total number of cards is divided by the numeral 3, the remainder is 2. Factors of 3 between 100 and 110 include 102, 105 and 108. Hence the numbers could be 101 (not possible), 104 and 107.
Fact 2 : If counted 4 at a time there is one left over. That means when the total number of cards are divided by 4, the remainder is 1. This is possible only in the case of 101
Fact 2 : If counted 4 at a time there is one left over. That means when the total number of cards are divided by 4, the remainder is 1. This is possible only in the case of 101