Great circles question
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- thucanh711
- Newbie | Next Rank: 10 Posts
- Posts: 3
- Joined: Sat Dec 23, 2017 2:48 am
Hi there,
hope my explanation could help you.
As O is the center of the circle and P, Q are on the circle => OP = OQ = r (the radius of the circle)
The area of the triangle can be calculated by: S = 1/2 sin($$\angle$$ POQ) OP. OQ = 1/2 . $$\frac{\sqrt{2}}{2}$$ . OP . OQ
We have S = 12 => the value of OP.OQ
OP.OQ = r. r = $$r^2$$
The area of the circle: S' = $$\pi.r^2$$
You can get your answer now.
hope my explanation could help you.
As O is the center of the circle and P, Q are on the circle => OP = OQ = r (the radius of the circle)
The area of the triangle can be calculated by: S = 1/2 sin($$\angle$$ POQ) OP. OQ = 1/2 . $$\frac{\sqrt{2}}{2}$$ . OP . OQ
We have S = 12 => the value of OP.OQ
OP.OQ = r. r = $$r^2$$
The area of the circle: S' = $$\pi.r^2$$
You can get your answer now.