students in the caf either like or dislike lima beans and brussel sprouts.
of these students 2/3 dislike llima beans, and of these 5/8 also dislike brussel sprouts, how many students like brussel sprouts but hate lima beans.
1. 120 students
2 40 like lima beans
is the answer 88?
venn diagram?
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Can someone expain how to solve this problem? I figured that the answer is E, but I wasn't comfortable with my approach. If x is total students, =>, 2/3x = DB(dislike beans), 5/8(2/3x) = 5/12x (DB+DS) . We cna eliminate (2) for sure as INSUFF. Considering (1), 80 = DB, 50 = DB+ DS(dislike sprouts). I didn't get any number for likes, but I wanted to know if my approach is right , and if there is a better way to approach this problem and how you would solve it.jopup wrote:students in the caf either like or dislike lima beans and brussel sprouts.
of these students 2/3 dislike llima beans, and of these 5/8 also dislike brussel sprouts, how many students like brussel sprouts but hate lima beans.
1. 120 students
2 40 like lima beans
is the answer 88?
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Hi
The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.
Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)
so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer
As per above , D should be answer
can anyone explain what's wrong here
The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.
Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)
so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer
As per above , D should be answer
can anyone explain what's wrong here
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I think you are right, both statement 1 and 2 are giving same information.....sanjaylakhani wrote:Hi
The question seems bit confusing.... if accroding to question eachs tudent has a opinion on both - sprouts and beans- means they either like or dislike beans- and like or sislike sprouts- then we can have an answer.
Students disliking beans are 80 as per A- now in this set- there are two subsets - students who like sprouts(numbering-30) snd student who do not like sprouts (numbering 50)
so overall numberr of students who dislike beans is 80 - of which who like sprouts is 30. So we have number - 30 as final answer
As per above , D should be answer
can anyone explain what's wrong here
I made a venn diagram ... and i think the answer should be D...
OA Please
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This question could be solved by Venn diagram.
Statement 1 says: Total students = 120.
Hence: Students who dislike Lima Beans = 120 * 2/3 = 80
Out of these, students who dislike Sprouts = 80 * 5/8 = 50
So total students who like sprouts but dislike beans = 80-50 = 30
So statement 1 is sufficient
Statement 2 says: 40 like Lima beans.
Hence 40 = 1/3 of total students, so total students = 120.
We can follow similar logic as above.
This statement is sufficient as well.
Answer IMO = D.
Statement 1 says: Total students = 120.
Hence: Students who dislike Lima Beans = 120 * 2/3 = 80
Out of these, students who dislike Sprouts = 80 * 5/8 = 50
So total students who like sprouts but dislike beans = 80-50 = 30
So statement 1 is sufficient
Statement 2 says: 40 like Lima beans.
Hence 40 = 1/3 of total students, so total students = 120.
We can follow similar logic as above.
This statement is sufficient as well.
Answer IMO = D.
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