Source: GMAT Prep
Two strings have equal length. One of the strings is shaped, with no overlap, into a circle. The other string is shaped, with no overlap, into a square. What is the ratio of the area of the region enclosed by the circle to the area of the region enclosed by the square?
A. \(1 : 2\)
B. \(\pi : 2\)
C. \(1 : 1\)
D. \(4 : \pi\)
E. The ratio depends on the length of the two strings
The OA is D
two strings have equal length. One of the strings is shaped, with no overlap, into a circle. The other string is shaped,
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- gmatter2012
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ans should be \4 \pi :1 \ rather than 4 : \ piBTGmoderatorLU wrote: ↑Wed Jan 12, 2022 5:46 pmSource: GMAT Prep
Two strings have equal length. One of the strings is shaped, with no overlap, into a circle. The other string is shaped, with no overlap, into a square. What is the ratio of the area of the region enclosed by the circle to the area of the region enclosed by the square?
A. \(1 : 2\)
B. \(\pi : 2\)
C. \(1 : 1\)
D. \(4 : \pi\)
E. The ratio depends on the length of the two strings
The OA is D
- gmatter2012
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ans should be \(4 \pi :1\) rather than \(4 : \pi \)BTGmoderatorLU wrote: ↑Wed Jan 12, 2022 5:46 pmSource: GMAT Prep
Two strings have equal length. One of the strings is shaped, with no overlap, into a circle. The other string is shaped, with no overlap, into a square. What is the ratio of the area of the region enclosed by the circle to the area of the region enclosed by the square?
A. \(1 : 2\)
B. \(\pi : 2\)
C. \(1 : 1\)
D. \(4 : \pi\)
E. The ratio depends on the length of the two strings
The OA is D
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L= length of stringsgmatter2012 wrote: ↑Mon Jan 17, 2022 8:02 amans should be \(4 \pi :1\) rather than \(4 : \pi \)BTGmoderatorLU wrote: ↑Wed Jan 12, 2022 5:46 pmSource: GMAT Prep
Two strings have equal length. One of the strings is shaped, with no overlap, into a circle. The other string is shaped, with no overlap, into a square. What is the ratio of the area of the region enclosed by the circle to the area of the region enclosed by the square?
A. \(1 : 2\)
B. \(\pi : 2\)
C. \(1 : 1\)
D. \(4 : \pi\)
E. The ratio depends on the length of the two strings
The OA is D
Circumference of circle=L=2piR
R=L/2pi.
Area of circle: piR^2= pi*L^2/4pi^2
= L^2/4pi
Each side of square= L/4
Area of square: L^2/16
Ratio of area of circle to area of square means:
Area of circle/Area of square
= (L^2/4pi)/(L^2/16)
= (L^2/4pi)*(16/L^2)
=4/pi which is 4:pi D