What is the area of the square whose two sides lie on the lines x + y = 2 and x + y = -2?
(A) 4 √2
(B) 8
(C) 8 √2
(D) 16
(E) 16 √2
[spoiler]Made up[/spoiler]
two sides lie
This topic has expert replies
- sanju09
- GMAT Instructor
- Posts: 3650
- Joined: Wed Jan 21, 2009 4:27 am
- Location: India
- Thanked: 267 times
- Followed by:80 members
- GMAT Score:760
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- shovan85
- Community Manager
- Posts: 991
- Joined: Thu Sep 23, 2010 6:19 am
- Location: Bangalore, India
- Thanked: 146 times
- Followed by:24 members
IMO B.sanju09 wrote:What is the area of the square whose two sides lie on the lines x + y = 2 and x + y = -2?
(A) 4 √2
(B) 8
(C) 8 √2
(D) 16
(E) 16 √2
[spoiler]Made up[/spoiler]
From the eqn x+y=2 and x+y=-2 we can get the points where the lines intersect X and Y axes.
The 4 points will be (2,0), (0,2), (-2,0), (0,-2).
These 4 points are the vertices as the X and Y axis distance between these points are 4 units each and they are perpendicular to each other.
Thus any one side can be the distance between (2,0) and (0,2) = 2*sqrt(2)
Thus area [2*sqrt(2)]^2 = 8 .
- neerajkumar1_1
- Master | Next Rank: 500 Posts
- Posts: 270
- Joined: Wed Apr 07, 2010 9:00 am
- Thanked: 24 times
- Followed by:2 members
the two lines are parallel with slope -1...
all we need to do is get the distance between the two lines... which will give the area of any square formed between the two lines...
there are several methods to find the distance between the two lines...
i have used the following..
y = x will be a line perpendicular to both the lines with a slope of 1
solving both the given lines with y=x
will give the points 1,1 and -1,-1 on the respective lines...
the distance between the two will = 2 root(2)* 2 root (2)
thus the area will be 8
Pick B
all we need to do is get the distance between the two lines... which will give the area of any square formed between the two lines...
there are several methods to find the distance between the two lines...
i have used the following..
y = x will be a line perpendicular to both the lines with a slope of 1
solving both the given lines with y=x
will give the points 1,1 and -1,-1 on the respective lines...
the distance between the two will = 2 root(2)* 2 root (2)
thus the area will be 8
Pick B
I also got B but I wasn't really sure. I graphed both of the lines and then simply drew a vertical line cutting what I thought the square would be in half. I got 4 for the diagonal of the square. Then you just use the xxsqrt2 formula and find the sides of the square equal 2sqrt2. Squaring 2sqrt2 gives you 8. So I think B? You should work for one of these companies, haha. This took more than 2 minutes .
- shovan85
- Community Manager
- Posts: 991
- Joined: Thu Sep 23, 2010 6:19 am
- Location: Bangalore, India
- Thanked: 146 times
- Followed by:24 members
FYI: After getting diagonal you can use (D^2)/2 [D=diagonal of square]Arcane66 wrote: I got 4 for the diagonal of the square. Then you just use the xxsqrt2 formula and find the sides of the square equal 2sqrt2. Squaring 2sqrt2 gives you 8. So I think B? You should work for one of these companies, haha. This took more than 2 minutes .
-
- Senior | Next Rank: 100 Posts
- Posts: 36
- Joined: Thu Dec 31, 2009 5:54 am
- Location: New York City
- Thanked: 2 times
I'm not sure what I'm doing wrong here..4 coordinates are (0,2) (2,0) (0, -2) and (-2, 0).
That means that the diagonal of the square is 4 so each side is 4/(sqrt 2).
Area = base x height = 4/(sqrt 2) * 4/(sqrt 2) = 8 x 1/2 = 4.
But thats not one of the answer..
That means that the diagonal of the square is 4 so each side is 4/(sqrt 2).
Area = base x height = 4/(sqrt 2) * 4/(sqrt 2) = 8 x 1/2 = 4.
But thats not one of the answer..
- sanju09
- GMAT Instructor
- Posts: 3650
- Joined: Wed Jan 21, 2009 4:27 am
- Location: India
- Thanked: 267 times
- Followed by:80 members
- GMAT Score:760
bdevas01 wrote:I'm not sure what I'm doing wrong here..4 coordinates are (0,2) (2,0) (0, -2) and (-2, 0).
That means that the diagonal of the square is 4 so each side is 4/(sqrt 2).
Area = base x height = 4/(sqrt 2) * 4/(sqrt 2) = 8 x 1/2 = 4.
But thats not one of the answer..
...because 4/(sqrt 2) * 4/(sqrt 2) = 16 x 1/2 = 8, man in hurry
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
-
- Senior | Next Rank: 100 Posts
- Posts: 36
- Joined: Thu Dec 31, 2009 5:54 am
- Location: New York City
- Thanked: 2 times
Sanju, i am not sure what you are implying.
The area of a triangle is (1/2)*(b*h)
Base X Height is 4/(sqrt 2) * 4/(sqrt 2), which I am certain is equal to 16/2 which equals 8.
Now 1/2 * 8 (because we still need to multiply by 1/2) = 4.
But 4 isn't an answer choice...
The area of a triangle is (1/2)*(b*h)
Base X Height is 4/(sqrt 2) * 4/(sqrt 2), which I am certain is equal to 16/2 which equals 8.
Now 1/2 * 8 (because we still need to multiply by 1/2) = 4.
But 4 isn't an answer choice...
- shovan85
- Community Manager
- Posts: 991
- Joined: Thu Sep 23, 2010 6:19 am
- Location: Bangalore, India
- Thanked: 146 times
- Followed by:24 members
Area of the Square is being asked... why r u bothering about the Trianglebdevas01 wrote:Sanju, i am not sure what you are implying.
The area of a triangle is (1/2)*(b*h)
Base X Height is 4/(sqrt 2) * 4/(sqrt 2), which I am certain is equal to 16/2 which equals 8.
Now 1/2 * 8 (because we still need to multiply by 1/2) = 4.
But 4 isn't an answer choice...
Read the question properly my friend...
-
- Senior | Next Rank: 100 Posts
- Posts: 36
- Joined: Thu Dec 31, 2009 5:54 am
- Location: New York City
- Thanked: 2 times
Got it! Thanks, I know such little errors in reading are common on the GMAT. I'll be taking things a slightly slower pace from now on.shovan85 wrote:Area of the Square is being asked... why r u bothering about the Trianglebdevas01 wrote:Sanju, i am not sure what you are implying.
The area of a triangle is (1/2)*(b*h)
Base X Height is 4/(sqrt 2) * 4/(sqrt 2), which I am certain is equal to 16/2 which equals 8.
Now 1/2 * 8 (because we still need to multiply by 1/2) = 4.
But 4 isn't an answer choice...
Read the question properly my friend...
Thanks again guys!
- pesfunk
- Master | Next Rank: 500 Posts
- Posts: 286
- Joined: Tue Sep 21, 2010 5:36 pm
- Location: Kolkata, India
- Thanked: 11 times
- Followed by:5 members
I drew the 2 lines and found 2 points 1,1 and -1,-1
Now, assuming that one of the sides of the square is the line touching the above 2 points,
I found the distance between these 2 points
distance = root [ (x1-x2)^2 + (y1-y2)^2) ]
found one of the sides as root (8)
So the area should be 8.
Now, assuming that one of the sides of the square is the line touching the above 2 points,
I found the distance between these 2 points
distance = root [ (x1-x2)^2 + (y1-y2)^2) ]
found one of the sides as root (8)
So the area should be 8.