Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y.

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Two equally sized jugs full of water are each emptied into two separate unequally sized empty jugs, X and Y. Now, jug X is 1/5 full, while jug Y is 2/3 full. If water is poured from jug X into jug Y until jug Y is filled, what fraction of jug X then contains water?

A. 0
B. 1/15
C. 2/15
D. 1/10
E. 2/10


OA D

Source: Veritas Prep

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Set the volumes of the equal jugs = A

So A= X/5 and 2Y/3. So Y= 3X/10

To fill Y from X requires Y-2Y/3 or Y/3 additional water.

Y/3 = (3X/10)/3 = X/10

Water remaining in X after this is poured into Y is then

X/5 - X/10 = [spoiler]X/10, D[/spoiler]