Hi there,
I took the Veritas Prep test this morning, which included the following question on the IR section:
For triangle JKL, angle JKL measures 90 degrees, and side JL has a length of 260 centimeters. If side JK > side KL, which of the following could be a combination of the lengths of sides JK and KL?
A) JK:
50
100
120
200
240
B) KL:
50
100
120
200
240
Answer for A): [spoiler] 240
[/spoiler]
Answer for B): [spoiler] 100
[/spoiler]
Since the question says that JK > KL, I knew JK could not be 50 and KL could not be 240 - I knocked down this combination. Then, I used the rule "the sum of any two sides of a triangle must be greater than the third side" to cross off A)/B) combinations 120/50, 120/100, and 200/50.
That left the following options:
A could be 240, in which case Y could be 50/100/120/200
A could be 200, in which case Y could be 50/100/120
At this point, I began using Pythagorean Theorem to figure out the answer but it just became too lengthy and time-consuming. How would I proceed to answer this question in another, more efficient way?
Thank you.
Solve 700-Level Algebra Qs In 90 Secs!
Master 700-level Inequalities and Absolute Value Questions
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease.
"Triangle JKL measures 90 deg" - Veritas Prep Test
This topic has expert replies
- krithika1993
- Junior | Next Rank: 30 Posts
- Posts: 16
- Joined: Sat Jul 23, 2016 4:38 am
-
- Senior | Next Rank: 100 Posts
- Posts: 33
- Joined: Wed Apr 06, 2016 7:08 am
- Thanked: 3 times
- Followed by:1 members
- GMAT Score:740
Hi Krithika
You have broken it down to a good extent already and I dont see a way out of pythagoras from where you are. Just one thing, for A = 200, B cannot be 50.
From hereon, you can ignore unit's digit for ease since all of the unit's digits are 0.
We know that 26^2 is 676. Hence you now have to work with only two scenarios. When A is 20 (0 ignored), you need B to be sqrt(676-400) and when A is 24, you need B to be sqrt (676 - 576) - this one has the answer for you.
I guess there is no way out of pythagoras here, but you can simply the things by dropping 0.
Cheers
You have broken it down to a good extent already and I dont see a way out of pythagoras from where you are. Just one thing, for A = 200, B cannot be 50.
From hereon, you can ignore unit's digit for ease since all of the unit's digits are 0.
We know that 26^2 is 676. Hence you now have to work with only two scenarios. When A is 20 (0 ignored), you need B to be sqrt(676-400) and when A is 24, you need B to be sqrt (676 - 576) - this one has the answer for you.
I guess there is no way out of pythagoras here, but you can simply the things by dropping 0.
Cheers
Gaurav
Blog: https://my-gmat-story.blogspot.in/?m=1
GMAT Prep - 1: 720
Kaplan Test - 1: 680
Kaplan Test - 2 710
Kaplan Test - 3: 720
MGMAT Test-1: 680
MGMAT Test-2: 720
MGMAT Test-3: 760
MGMAT Test-4: 720
GMAT Prep-2: 760
MGMAT Test-5: 740
GMAT: 740
Blog: https://my-gmat-story.blogspot.in/?m=1
GMAT Prep - 1: 720
Kaplan Test - 1: 680
Kaplan Test - 2 710
Kaplan Test - 3: 720
MGMAT Test-1: 680
MGMAT Test-2: 720
MGMAT Test-3: 760
MGMAT Test-4: 720
GMAT Prep-2: 760
MGMAT Test-5: 740
GMAT: 740
- [email protected]
- Legendary Member
- Posts: 2663
- Joined: Wed Jan 14, 2015 8:25 am
- Location: Boston, MA
- Thanked: 1153 times
- Followed by:128 members
- GMAT Score:770
Another little trick here: be on the lookout for classic pythagorean triples, in this case, 5x: 12x :13xkrithika1993 wrote:Hi there,
I took the Veritas Prep test this morning, which included the following question on the IR section:
For triangle JKL, angle JKL measures 90 degrees, and side JL has a length of 260 centimeters. If side JK > side KL, which of the following could be a combination of the lengths of sides JK and KL?
A) JK:
50
100
120
200
240
B) KL:
50
100
120
200
240
Answer for A): [spoiler] 240
[/spoiler]
Answer for B): [spoiler] 100
[/spoiler]
Since the question says that JK > KL, I knew JK could not be 50 and KL could not be 240 - I knocked down this combination. Then, I used the rule "the sum of any two sides of a triangle must be greater than the third side" to cross off A)/B) combinations 120/50, 120/100, and 200/50.
That left the following options:
A could be 240, in which case Y could be 50/100/120/200
A could be 200, in which case Y could be 50/100/120
At this point, I began using Pythagorean Theorem to figure out the answer but it just became too lengthy and time-consuming. How would I proceed to answer this question in another, more efficient way?
Thank you.
When you see 260, hopefully you recognize that it's a multiple of 13. If 13x = 260, x = 20, 5x = 100, and 12x = 240.