In a trial of a new drug, patients received a progressively growing dosage of the drug for a few days. On the first day, each patient received 15 milligrams of Drug. On each of the following days, the daily dosage was k milligrams greater than the dosage received the day before, reaching a dosage of 43 milligram on the last day of the trial. For how many days did the trial last, if each patient received a total amount of 145 milligrams of drug during the whole trial ?
(a) 4
(b) 5
(c) 6
(d) 7
(e) 9
OA:B
Trial of a new drug
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- HSPA
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Arth Series:
A = 15, d= k; An = 43; n/2 * (2A+ (n-1)d) = 145.. All these are sufficent to find n.
A = 15, d= k; An = 43; n/2 * (2A+ (n-1)d) = 145.. All these are sufficent to find n.
First take: 640 (50M, 27V) - RC needs 300% improvement
Second take: coming soon..
Regards,
HSPA.
Second take: coming soon..
Regards,
HSPA.
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Assume that the no of days = nadamz wrote:In a trial of a new drug, patients received a progressively growing dosage of the drug for a few days. On the first day, each patient received 15 milligrams of Drug. On each of the following days, the daily dosage was k milligrams greater than the dosage received the day before, reaching a dosage of 43 milligram on the last day of the trial. For how many days did the trial last, if each patient received a total amount of 145 milligrams of drug during the whole trial ?
(a) 4
(b) 5
(c) 6
(d) 7
(e) 9
OA:B
Day 1: 15
Day 2: 15 + k
Day n: 15 + (n-1)k
15 + (n-1)k = 43 .......... (1)
If we sum all these terms, we will have 15n, k*(The sum of an AP). The AP will be (1 + 2 + .. + (n-1))
so
15n + k(n-1)(2 + (n-2))/2 = 145 ........... (2)(I have used the formula for the sum of an AP)
Putting the value of (n-1)k from eqn (1) in eqn(2), we get,
15n + 14n = 145
so n = 5. Therefore, answer is B
- neelgandham
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From the question, The amount(in milligrams) of daily dosage of the drug is in AP.
(number of terms/2)*(First Term + Last Term) = Sum of the Terms
(number of days/2)*(First Dosage + Last Dosage) = Total amount
(number of days/2)*(15+43) = 145
(number of days)*(15+43)/2 = 145
(number of days)*29 = 145
(number of days = 5)
Answer : B
(number of terms/2)*(First Term + Last Term) = Sum of the Terms
(number of days/2)*(First Dosage + Last Dosage) = Total amount
(number of days/2)*(15+43) = 145
(number of days)*(15+43)/2 = 145
(number of days)*29 = 145
(number of days = 5)
Answer : B
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- Tani
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Try backsolving this one.
The dosage grew from 15 to 43 units, therefore the incremental dose on the last day was 28 units.
This means the total number of days in the study minus one (allowing the start day) has to be a factor of 28. Looking at our answer choices, only B works.
The dosage grew from 15 to 43 units, therefore the incremental dose on the last day was 28 units.
This means the total number of days in the study minus one (allowing the start day) has to be a factor of 28. Looking at our answer choices, only B works.
Tani Wolff
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Tani Wolff - Kaplan wrote:Try backsolving this one.
The dosage grew from 15 to 43 units, therefore the incremental dose on the last day was 28 units.
This means the total number of days in the study minus one (allowing the start day) has to be a factor of 28. Looking at our answer choices, only B works.
I did this exact thing!
I got the answer B by doing the following:
Since 43-15 = 28, again, we have to look for a factor of 28. I used 7.
Thus:
15 (add 7), 22 (add 7), 29 (add 7), 36 (add 7), 43 (add 7)
Add this up and we do end up getting the 145
So now we can see that it took 5 days
I hope this helps!
- Tani
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Good work!
My most difficult teaching task is often convincing my strongest math students to use backsolving and picking numbers. Even if you can solve tough problems using sophisticated math, you can often save time and gain confidence by using simple strategies. Also, when faced with a tricky problem you will have more tools at your disposal.
My most difficult teaching task is often convincing my strongest math students to use backsolving and picking numbers. Even if you can solve tough problems using sophisticated math, you can often save time and gain confidence by using simple strategies. Also, when faced with a tricky problem you will have more tools at your disposal.
Tani Wolff