If x, y, and z are integers greater than 1, and (3^27)(35^10)(z) = (5^8 )(7^10)(9^14)(x^y), then what is the value of x?
(1) z is prime
(2) x is prime
I can simplify the equation down to: 5^2*z=3*x^y but I need an explanation on why when x or z are prime you can solve for x.
(answer is D)
Appreciate any assistance I can get.
Chris
Tough DS, Please help
This topic has expert replies
-
- Junior | Next Rank: 30 Posts
- Posts: 10
- Joined: Mon Apr 02, 2007 8:30 pm
- givemeanid
- Master | Next Rank: 500 Posts
- Posts: 277
- Joined: Sun Jun 17, 2007 2:51 pm
- Location: New York, NY
- Thanked: 6 times
- Followed by:1 members
After simplifying, you get 5^2 * z = 3 * x^y
(1) z is prime.
Now, 3 on the right side has to be balanced by z because 5^2 doesn't have 3 as a factor. Since z is prime, z = 3
That means x^y = 5^2 and x = 5
(2) x is prime
5^2 has to be factored by x^y since 3 is not a factor of 5^2. If x is prime, then the only possibility is x = 5
Answer is (D)
(1) z is prime.
Now, 3 on the right side has to be balanced by z because 5^2 doesn't have 3 as a factor. Since z is prime, z = 3
That means x^y = 5^2 and x = 5
(2) x is prime
5^2 has to be factored by x^y since 3 is not a factor of 5^2. If x is prime, then the only possibility is x = 5
Answer is (D)
-
- Junior | Next Rank: 30 Posts
- Posts: 10
- Joined: Mon Apr 02, 2007 8:30 pm