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An urn contains g green marbles and b blue marbles. If 3 green marbles and 5 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
A. b/(b+g)
B. (b+5)/(g+3)
C. (b+5)/(b+g+8)
D. (b+5)/(b+g+3)
E. b/(b+g+5)
OA C
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An urn contains g green marbles and b blue marbles. If 3 green marbles and 5 blue marbles are added, and then one...
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Solution:AAPL wrote: ↑Sat Mar 27, 2021 4:21 pmVeritas Prep
An urn contains g green marbles and b blue marbles. If 3 green marbles and 5 blue marbles are added, and then one marble is selected at random from the urn, what is the probability that a blue marble will be drawn?
A. b/(b+g)
B. (b+5)/(g+3)
C. (b+5)/(b+g+8)
D. (b+5)/(b+g+3)
E. b/(b+g+5)
OA C
After 3 green marbles and 5 blue marbles are added, the total number of marbles in the urn is g + b + 3 + 5 = b + g + 8, and the number of blue marbles in the urn is b + 5. Therefore, the probability that a blue marble will be drawn is (b + 5) / (b + g + 8).
Answer: C
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