There are three parallel straight lines. Two points A and B are marked on the first line, points C and D are marked on the second line and points E and F are marked on the third line. Each of these six points can move to any position on its respective straight line. What is the maximum number of triangles that can be drawn from these points?
1) 41
2) 40
3) 18
4) 44
There are three parallel straight lines
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From the 6 points, ANY COMBINATION OF 3 can serve to form a triangle.mensanumber wrote:There are three parallel straight lines. Two points A and B are marked on the first line, points C and D are marked on the second line and points E and F are marked on the third line. Each of these six points can move to any position on its respective straight line. What is the maximum number of triangles that can be drawn from these points?
1) 41
2) 40
3) 18
4) 44
Thus:
Maximum number of triangles that can be formed from the 6 points = number of ways to choose 3 points from 6 options = 6C3 = (6*5*4)/(3*2*1) = 20.
The correct answer does not seem to be among the answer choices.
What is the source?
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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