The probability that \(B\) can shoot a target two out of two times is \(0.25.\) What is the probability that the target

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The probability that \(B\) can shoot a target two out of two times is \(0.25.\) What is the probability that the target will be missed by \(B\) immediately after such two shots?

A. \(0.25\)
B. \(0.5\)
C. \(0.75\)
D. \(0.4\)
E. \(0.8\)

OA B

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If the probability that B can shoot a target two out of two times is 0.25, then the probability of hitting the target in a single shot (let's denote it as P) is the square root of 0.25, because B must hit the target in both shots:
P = \(\sqrt{0.25}\) = 0.5

Now, we know that the probability of hitting the target in a single shot is 0.5.

The probability that the target will be missed by B immediately after such two shots is the complement of hitting the target, which is 1−P. Therefore, the probability of missing the target is:
1−0.5=0.5

So, the probability that the target will be missed by B immediately after such two shots is 0.5.

The correct answer is B

Bernard Baah
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