## The potential energy of a spring is given by the equation $$PE=\dfrac{kx^2}2$$ where $$k$$ is a constant and $$x$$ is

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### The potential energy of a spring is given by the equation $$PE=\dfrac{kx^2}2$$ where $$k$$ is a constant and $$x$$ is

by Vincen » Thu Oct 14, 2021 3:21 am

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## Global Stats

The potential energy of a spring is given by the equation $$PE=\dfrac{kx^2}2$$ where $$k$$ is a constant and $$x$$ is the distance the spring is stretched. If $$K =16$$ and the spring is stretched to $$2$$ feet and then to $$3$$ feet, how much potential energy is gained by the spring from the moment it is stretched $$2$$ feet to the moment it is stretched $$3$$ feet?

A. 200
B. 128
C. 72
D. 40
E. 32