## The figure above shows a rectangular parcel of undeveloped land partitioned into four regions, P, Q, R, and S.

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### The figure above shows a rectangular parcel of undeveloped land partitioned into four regions, P, Q, R, and S.

by BTGmoderatorLU » Sat Jul 24, 2021 5:00 pm

00:00

A

B

C

D

E

## Global Stats

Source: GMAT Paper Tests
The figure above shows a rectangular parcel of undeveloped land partitioned into four regions, P, Q, R, and S. In square meters, the area of square region Q is x^2, the area of rectangular region R is 5x, and the area of rectangular region P is 4x. What is the area, in square meters, of rectangular region S?

A. $$x^2-x$$
B. $$x^2+9x$$
C. $$20x-x^2$$
D. $$9$$
E. $$20$$

The OA is E

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### Re: The figure above shows a rectangular parcel of undeveloped land partitioned into four regions, P, Q, R, and S.

by swerve » Thu Jul 29, 2021 9:26 am
BTGmoderatorLU wrote:
Sat Jul 24, 2021 5:00 pm
Source: GMAT Paper Tests

AreaGeometry.PNG

The figure above shows a rectangular parcel of undeveloped land partitioned into four regions, P, Q, R, and S. In square meters, the area of square region Q is x^2, the area of rectangular region R is 5x, and the area of rectangular region P is 4x. What is the area, in square meters, of rectangular region S?

A. $$x^2-x$$
B. $$x^2+9x$$
C. $$20x-x^2$$
D. $$9$$
E. $$20$$

The OA is E
Area of $$Q = x^2$$; Side $$= x$$
Area of $$R = 5x = x \ast$$ length; length of $$R = 5$$
Area of $$P = 4x = x \ast$$ width; width of $$P = 4$$

Area of the entire plot $$=(x+4)\ast (x+5)=x^2+9x+20$$

Area of $$S=x^2+9x+20-x^2-5x-4x=20$$

Therefore, E

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