test23 3 13

okay here you go:

The only number which satisfies the given condition is : 101

and a(n)=a(1)+(n-1)d

199=100+(n-1)d

==> n=100 terms

Probability of selecting 1 number out of 100 numbers is 1/100 hence D

R

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Cybermusings: Legendary Member; Posts: 559; Joined: Tue Mar 27, 2007 1:29 am; Thanked: 5 times; Followed by:2 members

by Cybermusings » Wed Apr 25, 2007 6:06 am

Since we have to pick a number between 100 and 199 both inclusive...it is imperative that the hundreds digit is always 1....for the hundreds and last digit always to be 1 more than the middle digit...the last digit has to be 1 and the middle digit 0

There is only 1 such number i.e. 101

So probability = 1/100

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