Can anyone explain this problem to me?
the temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees fahrenheit. if the temperature f of the coffee t minutes after it was poured can be determined by the formula f=120(2^-at) + 60, where f is in degrees fahrenheit and a is a constant, then the temperature of the coffee 30 minutes after it was poured was how many degrees faherenheit?
thanks a lot.
Temperature word problem
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- Morgoth
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Insert the value of f=120 and t=10 to find the value of constantmsquare wrote:Can anyone explain this problem to me?
the temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees fahrenheit. if the temperature f of the coffee t minutes after it was poured can be determined by the formula f=120(2^-at) + 60, where f is in degrees fahrenheit and a is a constant, then the temperature of the coffee 30 minutes after it was poured was how many degrees faherenheit?
thanks a lot.
f=120(2^-at) + 60
120 = 120(2^-a10) + 60
120-60 = 120(2^-a10)
60/120 = (2^-a10)
1/2 = 1/2^a10
a10 = 1
a = 1/10
now substitute the value of t=30 & a=1/10 to find f
f=120(2^-30/10) + 60
f = 120 * 1/2^3 + 60
f = 120/8 + 60
f = 15+60 = 75
Hope this helps.
- sanju09
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Let’s put the available values in the given relation to reveal more of it, putting values we get:msquare wrote:Can anyone explain this problem to me?
the temperature of a certain cup of coffee 10 minutes after it was poured was 120 degrees fahrenheit. if the temperature f of the coffee t minutes after it was poured can be determined by the formula f=120(2^-at) + 60, where f is in degrees fahrenheit and a is a constant, then the temperature of the coffee 30 minutes after it was poured was how many degrees faherenheit?
thanks a lot.
120 = 120 (2^-a*10) + 60
» 2 = 2 (2^-a*10) + 1
» 2 (2^-a*10) = 1
» (2^-a*10) = ½
» (2^-a*10) = 2^-1
» -a*10 = -1
» a = 1/10.
So the modified relation is f = 120 (2^-t/10) + 60, and when t = 30, f = 120 (2^-3) + 60 = 15 + 60 = 75 º Fahrenheit.
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Sanjeev K Saxena
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Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com