## The mean of twenty-five consecutive positive integers numbers is what percent of the total?

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### The mean of twenty-five consecutive positive integers numbers is what percent of the total?

by BTGmoderatorLU » Thu Feb 24, 2022 10:33 am

00:00

A

B

C

D

E

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Source: Magoosh

The mean of twenty-five consecutive positive integers numbers is what percent of the total?

A. 4%
B. 5%
C. 20%
D. 25%
E. Cannot be determined by the information provided.

The OA is A

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### Re: The mean of twenty-five consecutive positive integers numbers is what percent of the total?

by Brent@GMATPrepNow » Thu Feb 24, 2022 12:11 pm
BTGmoderatorLU wrote:
Thu Feb 24, 2022 10:33 am
Source: Magoosh

The mean of twenty-five consecutive positive integers numbers is what percent of the total?

A. 4%
B. 5%
C. 20%
D. 25%
E. Cannot be determined by the information provided.

The OA is A
----------ASIDE----------------------
There's a nice rule that says, "In a set where the numbers are equally spaced, the mean will equal the median."
For example, in each of the following sets, the mean and median are equal:
{7, 9, 11, 13, 15}
{-1, 4, 9, 14}
{3, 4, 5, 6}
------------------
For this question, let x = first value
So, x+1 = second value
x+2 = third value
.
.
.
x+24 = last value

This means x+12 is the median AND the mode

Since x+12 = the mean of the 25 numbers, we can conclude that (25)(x+12 ) = the SUM of the 25 numbers

The mean of twenty-five consecutive positive integers numbers is what percent of the total?
We must convert (x+12)/(25)(x+12) to a PERCENT
(x+12)/(25)(x+12) = 1/25
= 4/100
= 4%
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### Re: The mean of twenty-five consecutive positive integers numbers is what percent of the total?

by regor60 » Fri Feb 25, 2022 3:56 pm
Call the sum of the 25 integers S.

So the mean of the integers is:

S/25

The mean is what percent of S ?

(S/25)/S = 1/25 = 4/100 =[spoiler]4%,A[/spoiler]

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