The arithmetic mean of the 5 consecutive integers starting with 's' is 'a'. What is the arithmetic mean of 9 consecutive integers that start with s + 2?
A. 2 + s + a
B. 2 + a
C. 2 s
D. 2 a + 2
E. 4 + a
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sanju09
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vivek.kapoor83
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5 consecutive no. will be
s,s+1,s+2,s+3,s+4
adding 5 nos and dividin by 5
(5s+10)/5 = a
s = a-2 .........eq(1)
now, s+2...9 consective integers
adding all 9 will give : 9s+54
AM = (9s+54)/9
AM = s+6
put s = a-2 from eq (1)
AM = a-2+6
AM = a+4
Hence E.
s,s+1,s+2,s+3,s+4
adding 5 nos and dividin by 5
(5s+10)/5 = a
s = a-2 .........eq(1)
now, s+2...9 consective integers
adding all 9 will give : 9s+54
AM = (9s+54)/9
AM = s+6
put s = a-2 from eq (1)
AM = a-2+6
AM = a+4
Hence E.
