Problem Solving

so I got stuck at a question which uses sqrt(x^2)=|x| which I understand. However, if I'm correct in my power laws isn't it also x?

sqrt(x^2)=(x^2)^1/2, then multiplying in the exponents = x^1 which is x? but clearly this isn't the case?

maybe I'm doing something wrong and the answer could be very obvious.

shstylo wrote:so I got stuck at a question which uses sqrt(x^2)=|x| which I understand. However, if I'm correct in my power laws isn't it also x?

sqrt(x^2)=(x^2)^1/2, then multiplying in the exponents = x^1 which is x? but clearly this isn't the case?

maybe I'm doing something wrong and the answer could be very obvious.

As per the laws of exponents , value of even power of any number can have the base as +ve or -ve.

As in case of X^2 , value of X can be +ve or -ve.

Please post the exact problem to get the precise help out of the forum.

There is a difference in the two although it's bit confusing..
let's say-
x^2=4 => x= 2,-2
but sqrt(4)=2
It would be more clear by this e.g.
sqrt(sqrt(16))=sqrt(4)=2 { bcoz sqrt for negative numbers is not defined)