All,
Can some one please solve this question for me. Its a similar triangle problem which was on test 2 of the official gmat.
Either there is a simple property of triangles (similar triangle) that I dont know off , or this is surely a difficulty level 5 question.
Thanks,
-Anshul
Similar triangles
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which is the answer. C or e
I would have guessed 2s as 1/2 *b*h=b*h of bigger if the area of bigger is twice that of smaller.
So in terms of smaller s1, big s would be just twice 2s.
Khurram
I would have guessed 2s as 1/2 *b*h=b*h of bigger if the area of bigger is twice that of smaller.
So in terms of smaller s1, big s would be just twice 2s.
Khurram
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The answer is C.
I had to google this one.
https://www.mathwarehouse.com/geometry/s ... angles.php
Essentially for similar triangles
Ratio of Areas = square ( Ratio of sides )
Here ratio of areas is given as 2, therefore ratio of sides is sqrt(2)
I had to google this one.
https://www.mathwarehouse.com/geometry/s ... angles.php
Essentially for similar triangles
Ratio of Areas = square ( Ratio of sides )
Here ratio of areas is given as 2, therefore ratio of sides is sqrt(2)
Aha !! Thanks ...
The correct answer is indeed C.
But seriously they expect us to know "THIS" property of similar triangles. Just glad , that no one knew this at the top of their head and i wasnt missing on something too obvious.
Thanks again!!
-A
The correct answer is indeed C.
But seriously they expect us to know "THIS" property of similar triangles. Just glad , that no one knew this at the top of their head and i wasnt missing on something too obvious.
Thanks again!!
-A
A simple thing to keep in mind is that the ratio of sides for similar traingles is same. So in the given question ...Area of larger traingle is twice i.e.
1/2SH = 2*1/2sh
=> SH = 2*sh (where H is the height of big tr and h is height of smaller one)
Also as they are similar trs
S/s = H/h => H = S*h/s
Putting this value of H in the above equation ..u get S = sqrt2*s
1/2SH = 2*1/2sh
=> SH = 2*sh (where H is the height of big tr and h is height of smaller one)
Also as they are similar trs
S/s = H/h => H = S*h/s
Putting this value of H in the above equation ..u get S = sqrt2*s
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Remember... area is a square function, length is linear.
So, if you double all the lengths, you'll 2^2 = quadruple the area. If you triple all the lengths, you'll 3^2 = nontuple (no clue if that's a real word, by the way!) the area.
So, if you double all the lengths, you'll 2^2 = quadruple the area. If you triple all the lengths, you'll 3^2 = nontuple (no clue if that's a real word, by the way!) the area.
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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