Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $605 as interest. What was the value of his total savings before investing in these two bonds?
A. $5500
B. $11000
C. $22000
D. $2750
E. $44000
OA: D
Shawn invested one half of his savings in a bond
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Hmm... I probably did this an unorthodox way but here goes nothing.Musicat wrote:Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $605 as interest. What was the value of his total savings before investing in these two bonds?
A. $5500
B. $11000
C. $22000
D. $2750
E. $44000
OA: D
First, recognize that simple interest accrues at a constant rate over any time interval. The only relevant sum is the initial principal. So, the $550 in simple interest accrued over two years means he earns $275 in simple interest each and every year.
Now, this also means on the compounded interest bond, he also earned $275 in interest in Year 1 (because it has not yet compounded and the principal and interest rate are identical to the other bond). It follows then that he makes $330 in interest in Year 2 on that bond (605 - 275 = 330).
From this we can make the following equations:
275 = P*r, where P = A/2 (A being the value we are trying to solve for, i.e. the initial savings)
330 = (P+Pr)*r (from the compounded interest bond - he now has P+Pr at the start of year 2 and earns interest at rate r, which totals $330)
We already know Pr = 275, so substituting that into our second equation & then simplifying:
330 = (P + 275)r
330 = Pr + 275r
Substituting Pr = 275 again...
330 = 275 + 275r
55 = 275r
r = 0.2
This means the interest rate was 20%.
We can use this value of r to solve for P using our first equation, and then double P to find A.
275 = P/5
P = 1375
So A = 2P = 2750 and the answer is D.
800 or bust!
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Let's say he saved 2x dollars.
The x at simple interest gives us x * p/100 * 2 = 550.
The x at compound interest gives us x * (1 + p/100) * (1 + p/100) = x + 605.
The first equation gives us p/100 = 275/x.
Replacing p/100 with 275/x in the second equation:
x * (1 + 275/x) * (1 + 275/x) = x + 605
x * (1 + 550/x + 275²/x²) = x + 605
x + 550 + 275²/x = x + 605
275²/x = 55
275² = 55x
275 * 5 = x
Since the savings is 2x, we just double this, for 275 * 5 * 2, or D.
The x at simple interest gives us x * p/100 * 2 = 550.
The x at compound interest gives us x * (1 + p/100) * (1 + p/100) = x + 605.
The first equation gives us p/100 = 275/x.
Replacing p/100 with 275/x in the second equation:
x * (1 + 275/x) * (1 + 275/x) = x + 605
x * (1 + 550/x + 275²/x²) = x + 605
x + 550 + 275²/x = x + 605
275²/x = 55
275² = 55x
275 * 5 = x
Since the savings is 2x, we just double this, for 275 * 5 * 2, or D.