Sets

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Sets

by rajs.kumar » Thu Oct 26, 2006 2:35 am
One night a certain motel rented 3/4 of its rooms, including 2/3 of its air-conditioned rooms. If 3/5 of its rooms were air-conditioned, what percent of the rooms that were not rented were air-conditioned.

A. 20%
B. 331/3%
C. 35%
D. 40%
E. 80%

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by ajith » Thu Oct 26, 2006 2:59 am
((1-2/3)*3/5)/(1-3/4)

=(1/5)/(1/4)=(4/5)=80%

So I go for E

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by countingdolls » Thu Oct 26, 2006 7:31 am
80% it is.

In case you find it difficult to use the fractions, assume the total no of rooms to be a value, say 100........problem becomes easier