Variable as an exponent

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Variable as an exponent

by Rastis » Thu Nov 27, 2014 10:42 am
Is 5^k less than 1000?

1) 5^k+1 > 3000

2) 5^k-1 > 5^k - 500

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by Brent@GMATPrepNow » Thu Nov 27, 2014 11:03 am
NOTE: Your transcription is somewhat misleading. I've added some brackets to avoid any ambiguity.
Is 5^k less than 1,000?

(1) 5^(k+1) > 3,000
(2) 5^(k-1) = 5^k - 500
Target question: Is 5^k less than 1000?

Statement 1: 5^(k+1) > 3000
Notice that 5^1 = 5, 5^2 = 25, 5^3 = 125, 5^4 = 625, 5^5 = 3125...

There are several values of k that satisfy the condition that 5^(k+1) > 3000. Here are two:
case a: k = 4 [so, 5^(k+1) = 5^5 = 3125, which is greater than 3000]. In this case 5^k = 5^4 = 625, and 625 IS less than 1000.
case b: k = 5 [so, 5^(k+1) = 5^6 = 15625, which is greater than 3000]. In this case 5^k = 5^5 = 3125, and 3125 is NOT less than 1000.
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT.

Statement 2: 5^(k-1) = 5^k - 500
IMPORTANT: Notice that we're given an EQUATION, which means we can solve the equation to find the definitive value of k. If we can find the value of k, then we can instantly tell whether or not 5^k is less than 1000. So, it SEEMS that we can conclude that statement 2 is sufficient WITHOUT performing any calculations. HOWEVER, if it's the case that the equation yields 2 possible values of k, then it may be the case that one value of k is such that 5^k is less than 1000, and the other value of k is such that 5^k is greater than 1000. So, at this point, we need only determine whether or not the equation will yield 1 or 2 values of k.

Rearrange to get the k's on one side: (5^k) - 5^(k-1) = 500
Factor the left side: 5^(k-1)[5 - 1] = 500
Simplify: 5^(k-1)[4] = 500
STOP!!
At this point, we can see that this equation will yield only one value of k. So, IF WE WERE to solve the equation for k, we would definitely be able to determine whether or not 5^k is less than 1000.
Since we can answer the target question with certainty, statement 2 is SUFFICIENT.

Answer = B

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by GMATGuruNY » Thu Nov 27, 2014 6:23 pm
Is 5^k less than 1,000?

(1)5^(k+1) > 3,000
(2)5^(k-1) = 5^k - 500
LIST the powers of 5:
5¹ = 5
5² = 25
5³ = 125
5� = 625
5� = 3125.

Statement 1: 5^(k+1) > 3000
It's possible that k=4, since 5^(4+1) = 5� = 3125.
In this case, 5^k = 5� = 625, which is LESS than 1000.

It's possible that k=10, since 5^(10+1) = 5¹¹ = something HUGE.
In this case, 5^k = 5¹�, which is GREATER than 1000.
INSUFFICIENT.

Statement 2: 5^(k-1) = 5^k - 500
5^k - 5^(k-1) = 500.
The terms on the left represent two powers of 5 that are 500 apart.
The required values can be seen in our list above:
5^k = 5� = 625.
5^(k-1) = 5³ = 125.
Thus, 5^k = 5� = 625, which is LESS than 1000.
SUFFICIENT.

The correct answer is B.
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by [email protected] » Thu Nov 27, 2014 8:58 pm
Hi Rastis,

Both Brent and Mitch have provided some valuable insight into this question. Here's another set of rules to keep in mind (that involve exponent rules):

First, 5^(k+1) is 5 times the value of 5^k.

Using exponent rules, here's why:

(5^k)(5^1) = 5^(k+1)


Second, 5^k is 5 times the value of 5^(k-1)

Using a different exponent rule, here's why:

(5^k)/(5^1) = 5^(k-1)

So, in Fact 1, when we're told...

5^(k+1) > 3,000

We can divide both sides by 5^1....

[5^(k+1)]/5^1 = 5^k

3,000/5 = 600

5^k > 600

The question asks if 5^k is less than 1,000?

We know that 5^k > 600

If 5^k = 601, then the answer to the question is YES
If 5^k = 1,001, then the answer to the question is NO
Fact 1 is INSUFFICIENT

Fact 2 gives us 1 equation with 1 variable. As the other explanations show, you CAN solve it.
Fact 2 is SUFFICIENT

Final Answer: B

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