Search found 31 matches
By that logic, I would rule out B, D & E for the word "singel" 
I think it is a typo.
IMO D is the best answer!
- by chintudave
Sun Feb 15, 2009 10:28 pm- Forum: Sentence Correction
- Topic: DNA
- Replies: 8
- Views: 1720
The parallelism starts after "are"
(C) that local witnesses are difficult to locate, reticent, and The parallel construct starts after the word "are", that the local witnesses are .... difficult to locate that the local witnesses are .... reticent and that the local witnesses are .... suspicious of strangers All three (&quo...
- by chintudave
Sat Feb 14, 2009 11:12 am- Forum: Sentence Correction
- Topic: Federal Authorities.
- Replies: 12
- Views: 7045
Answer Set
(1/16)^-1/4
= 16 ^ 1/4
i.e. 4th root of 16.
As others have said the answer is 4... however if this question shows up in DS... the options are 2, -2, 2i & -2i... so there is no single value to this problem.
- by chintudave
Fri Jan 30, 2009 10:52 pm- Forum: Problem Solving
- Topic: Law of Exponents
- Replies: 5
- Views: 1292
OA ?
IMO your algebra is correct. That is if i interpret the question correctly. What is the answer and what was the miss ?
- by chintudave
Fri Jan 30, 2009 7:57 pm- Forum: Problem Solving
- Topic: geometry confusion
- Replies: 5
- Views: 1516
- by chintudave
Wed Jan 28, 2009 5:33 pm- Forum: Critical Reasoning
- Topic: Try this
- Replies: 11
- Views: 2171
Let the time taken by J to mow the lawn is x. Then, time taken by R is x + 50 In the first 20 minutes, the fraction of lawn mowed by J is 20/x So fraction of lawn remaining for R is (1 - 20/x) The time taken by R to mow the remaining lawn would be a product of 1. The fraction of lawn remaining 2. Ti...
- by chintudave
Tue Jan 27, 2009 11:52 pm- Forum: Problem Solving
- Topic: Work problem - Janice can mow the lawn . . .
- Replies: 3
- Views: 1323
Grades of Milk
This is very straight forward.
0.1x + 0.2y + 0.3z = 0.15(x + y + z)
0.1x + 0.2y + 0.3z = 0.15x + 0.15y + 0.15z
Solving the equation...
0.05x = 0.05y + 0.15z
x = y + 3z
- by chintudave
Sun Jan 25, 2009 10:50 pm- Forum: Problem Solving
- Topic: GMAT prep Prob solv qs
- Replies: 12
- Views: 2221
Two type of machines... Type R & S
Type R does the work in 36 hours. So in 1 hour R does 1/36th portion of the work. Type S does the work in 18 hours. So in 1 hour S does 1/18th portion of the work. So together R & S in an hour will do 1/36 + 1/18 = 3/36 = 1/12th portion of the work. i.e They take 12 hours to complete the work. N...
- by chintudave
Sun Jan 25, 2009 10:44 pm- Forum: Problem Solving
- Topic: GMAT prep Prob solv qs
- Replies: 12
- Views: 2221
Q: Sum a1 + a2 + ... an is either .... I would start with dividing 350 / 7 = 50. Since 50 is not an option there has to be at least one term that is 77. So 350 - 77 = 273 273/7 = 39 times so the total is 39 times 7 and 1 time 77 so n is 39 + 1 = 40 However I would also negate the option of having tw...
- by chintudave
Sun Jan 25, 2009 10:26 pm- Forum: Problem Solving
- Topic: GMAT prep Prob solv qs
- Replies: 12
- Views: 2221
Gear Revolutions
P - 10 revolutions per minute i.e. 6 seconds per revolution
Q - 40 revolutions per minute i.e. 1.5 seconds per revolution
So in 6 seconds Q has 3 additional revolutions than P.
So for 6 additional revolutions the time would be 12 seconds.
- by chintudave
Sun Jan 25, 2009 10:16 pm- Forum: Problem Solving
- Topic: GMAT prep Prob solv qs
- Replies: 12
- Views: 2221
(1/5)^m * (1/4)^18 = 1/2(10)^35
(1/5)^m = (1/2(10)^35) / (1/4)^18
(1/5)^m = (4^18) / 2(10)^35
(1/5)^m = (2^2^18) / 2(10)^35
(1/5)^m = 2^36 / 2(10)^35
(1/5)^m = 2^35 / 10 ^ 35
(1/5)^m = 2^35 / 2^35 * 5^35
(1/5)^m = 1/5^35
Hence m = 35
- by chintudave
Sun Jan 25, 2009 10:07 pm- Forum: Problem Solving
- Topic: GMAT prep Prob solv qs
- Replies: 12
- Views: 2221
IMO - E
Had the x intercept been > 10 the two statements taken together would have solved the problem.
- by chintudave
Sat Jan 24, 2009 11:11 am- Forum: Data Sufficiency
- Topic: GMAT prep
- Replies: 4
- Views: 1618
What is the OA ?
IMO - D 3/5 I do not see this problem as conditional probability. Total number of combination - 6C4 i.e 15 Total number of combination for two boys - 3C2 i.e 3 Total number of combination for two girls - 3C2 i.e 3 So total number of 2 boys and 2 girls is 3C2 * 3C2 = 9 So probability is 9/15 = 3/5 = D
- by chintudave
Fri Jan 23, 2009 10:44 pm- Forum: Problem Solving
- Topic: Probability Question
- Replies: 17
- Views: 4204
I would stick with awesomeusername's method for the 1 problem.
Here is my stab at the second one...
V* = V-V/3
i.e. V* is nothing but two third V... 2V/3
Extending the above ... (V*)* = 4V/9
Given 4V/9 = 8, so V = 18
- by chintudave
Wed Jan 21, 2009 8:54 pm- Forum: Problem Solving
- Topic: Two problems that are giving me hell
- Replies: 9
- Views: 1547
My 2 cents...
Ratio B:G is 3:4... so total parts 7 (3+4)
Difference in ratio is 1/7 i.e (4-3)/7 which is given as 5
And girls are 4 parts of 7 i.e 4(1/7) = 4*5 = 20
- by chintudave
Mon Jan 19, 2009 11:04 pm- Forum: Problem Solving
- Topic: Question 5 (nov.14th)
- Replies: 6
- Views: 6842