Search found 43 matches
Hey Eric, Great Post, I have under one month left for my GMAT exam(4th August). I have been preparing since last month and I have completed Manhattan GMAT 8 study Guides, but my preparation has been getting hampered with work/relatives/vacations. With just one month left, I am left with Kaplan 800 a...
- by champ0007
Thu Jul 07, 2011 2:43 am- Forum: GMAT Strategy
- Topic: How to study for the GMAT under one month
- Replies: 28
- Views: 249905
- by champ0007
Thu Jul 07, 2011 2:41 am- Forum: GMAT Strategy
- Topic: How to study for the GMAT under one month
- Replies: 28
- Views: 249905
If they would have added gold, so the methods used would have been correct to not to find any gold! Yeah ...i think I am getting it. I think you meant if they would have added Gold to the samples, so the methods would have been ACCURATE to have reported high gold content.. But without Gold samples ...
- by champ0007
Fri Jun 24, 2011 11:15 am- Forum: Critical Reasoning
- Topic: Assumption Question
- Replies: 6
- Views: 1753
- by champ0007
Thu Jun 23, 2011 11:40 am- Forum: Sentence Correction
- Topic: Studies of test
- Replies: 5
- Views: 1186
"Does not call X into Question? " - Does that mean - Find the option that does not challenge John's Conclusion ?
Is that the way we can interpret the Question asked ?
Can anyone pls suggest?
Based on that interpretation my answer would be C
Thanks
- by champ0007
Thu Jun 23, 2011 11:32 am- Forum: Critical Reasoning
- Topic: I FIND THIS MGMAT QN ODD ! PLEASE EXPLAIN
- Replies: 6
- Views: 1895
- by champ0007
Thu Jun 23, 2011 11:24 am- Forum: Critical Reasoning
- Topic: OMG!!..how likely to come in GMAT..Please help
- Replies: 7
- Views: 2236
Premise 1 - F's samples examined for high gold content Premise 2 - 2 mining expeditions ordered - no gold found Premise 3 - modern analysis indicated low gold content Conclusion - Methods by which F's samples were examined were inaccurate We have to find an assumption that links the Premises logical...
- by champ0007
Thu Jun 23, 2011 11:18 am- Forum: Critical Reasoning
- Topic: Assumption Question
- Replies: 6
- Views: 1753
Assume the length and breadth of the picture to be L and B respectively. Area of the picture = LB Area of frame = 18 * 15 - Area of picture = 270 - LB Condition 1 - Area of picture is equal to area of the frame therefore, LB = 270 - LB 2LB = 270 LB = 135 ------(1) Condition 2 L/B = 18/15 L/B = 6/5 -...
- by champ0007
Wed Jun 15, 2011 6:58 pm- Forum: Problem Solving
- Topic: rectangular question
- Replies: 1
- Views: 808
Thanks GMATGuruNY, I could understand your solution, but how do I know when to use exponential growth or Geometric Progression? using Exponential Growth -> 40 million = 5 million * x^6 using GP -> 40 million = 5 million * x^5 [i.e. a(r^(n-1)) ] it sounded like a GP case to me ... but having x^6 made...
- by champ0007
Mon Jun 13, 2011 1:13 pm- Forum: Problem Solving
- Topic: MGMAT - Formulas & Functions Advanced Problem
- Replies: 3
- Views: 1554
|-9| is in the numerator ...
66/((-33) x |-9|) ---> -2/9 which is what you are getting...
66\(-33) x |-9| = (66 x |-9|) / (-33) = -18
Just check it out
- by champ0007
Mon Jun 13, 2011 12:59 pm- Forum: GMAT Math
- Topic: silly math question
- Replies: 9
- Views: 2069
MGMAT - Formulas & Functions Advanced Problem
A strain of bacteria multiplies such that the ratio of its population in any two consecutive minutes is constant. If the bacteria grows from a population of 5 million to 40 million in one hour, by what factor does the population increase every 10 minutes? I did not understand the answer explanation,...
- by champ0007
Mon Jun 13, 2011 12:46 pm- Forum: Problem Solving
- Topic: MGMAT - Formulas & Functions Advanced Problem
- Replies: 3
- Views: 1554
- by champ0007
Sun Jun 12, 2011 2:42 am- Forum: Problem Solving
- Topic: sum of even numbers
- Replies: 5
- Views: 6225
Answer is 16 Rule- Greatest number with which if we divide p,q,r and it leaves same remainder in each case... Number is of form = HCF of (p-q),(p-r) Therefore, HCF of (215-167), (213-135) = HCF of 48, 80 = 16. 215 / 16 ---> Remainder is 7 167 / 16 ---> Remainder is 7 135 / 16 ---> Remainder is 7
- by champ0007
Sun Jun 12, 2011 2:02 am- Forum: Problem Solving
- Topic: Number properties
- Replies: 5
- Views: 2420
1:14 10 digits, 3 area code is known and next 5 digits known thus unknown=2 digits no. can be 2,3,6,8,9 total options=5*5=25 if in 1st attempt then 1/25 if in second, (24/25)*(1/24) = 1/25 total=2/25 = 50/625 IMO E I understood till 1/25 for first attempt and 24/25 * 1/24 for second attempt.. I did...
- by champ0007
Wed Jun 08, 2011 11:58 am- Forum: Problem Solving
- Topic: Probability Again!!
- Replies: 14
- Views: 3356
- by champ0007
Wed Jun 08, 2011 11:29 am- Forum: Problem Solving
- Topic: Good Question
- Replies: 7
- Views: 1287