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Simple Algebra
Hey all - this is a simple question from a Kaplan workbook. If (q)(34)(36)(38) = (17)(18)(19) then q =? Am I missing something... this is a pretty easy question, but I am getting the wrong answer. Here is my method (where is my logic askew?) (q)(34)(36)(38) = (17)(18)(19) Factor out the two on the L...
- by franciskyle
Sat Mar 28, 2009 5:07 pm- Forum: Problem Solving
- Topic: Simple Algebra
- Replies: 3
- Views: 1307
I arrived at a different answer for the triangle question. I looked at it the following way... is there a mistake in my logic?
eqn 1: S = (B*H)/2
and
eqn 2: 2s = (B*H)/2
Therefore
Rearrange eqn 2: 2s = (B*H)/2 --> B*H = 4s
Plug eqn 2 into eqn 1
S = (4s)/2
Therefore
S = 2s
- by franciskyle
Sat Mar 14, 2009 6:34 pm- Forum: Problem Solving
- Topic: GMAT Prep - triangle and aveage problem
- Replies: 4
- Views: 2384
You could immediately draw the below equation from the problem - X being the fourth test score.
(3*85 + X)/4 = 87
Therefore X = 93
- by franciskyle
Sat Mar 14, 2009 6:22 pm- Forum: Problem Solving
- Topic: Average
- Replies: 5
- Views: 1474
- by franciskyle
Fri Mar 13, 2009 11:35 pm- Forum: GMAT Essays (AWA)
- Topic: Essay Score
- Replies: 1
- Views: 1639
- by franciskyle
Fri Mar 13, 2009 12:42 am- Forum: Problem Solving
- Topic: Function
- Replies: 9
- Views: 1932
I have seen this question before, and I think that D should actually be 2/3 not 2x. That would make it possible to solve. All you need to do for this one is plug A+B, A & B into each respective equation to see if they equate. A: (A+B)^2 NOT= A^2 + B^2 B: (A + B) + 1 NOT= (A+1) + (A+1) C: sqrt(A+...
- by franciskyle
Fri Mar 13, 2009 12:41 am- Forum: Problem Solving
- Topic: Function
- Replies: 9
- Views: 1932
- by franciskyle
Thu Mar 12, 2009 9:14 pm- Forum: Problem Solving
- Topic: Series
- Replies: 10
- Views: 2688
2x + 24y = 124 Rearrange: 24y = (124 - 2x) Now quickly go through the solutions (y must equal an integer). A: 24y = 26, therefore no good B: 24y = 54, therefore no good C: 24y = 48, therefore this is a solution, since y = 2 D: 24y = 68, therefore no good E: 24y = 72, therefore this is ALSO a solutio...
- by franciskyle
Thu Mar 12, 2009 9:06 pm- Forum: Problem Solving
- Topic: Series
- Replies: 10
- Views: 2688
Pattern = 6 Digits long
44 / 6 = 7 R 2
Therefore the hundredths digit (because remainder 2) should be the same as the 44th digit.
9
- by franciskyle
Thu Mar 12, 2009 8:47 pm- Forum: Problem Solving
- Topic: Repeating decimal
- Replies: 3
- Views: 2191
Is the hypotenuse of an inscribed (circle) right triangle always the diameter?krisraam wrote:41,40,9 forms a right triangle.
So the diameter is 41.
- by franciskyle
Thu Mar 12, 2009 8:40 pm- Forum: Problem Solving
- Topic: Geometry, Circumscribe
- Replies: 4
- Views: 1618
Hi cramya... I find the way you solved this problem interesting. The easy way to do it would be to break down 130 in to its prime factors first 130 =2*5*13 = 2^1*5^1*13^1 Now to find the number of factors add 1 to the exponent of each prime factor and multiply (1+1) (1+1) (1+1) = 8 unique factors Ar...
- by franciskyle
Thu Mar 12, 2009 7:22 pm- Forum: Problem Solving
- Topic: Arithmetic
- Replies: 6
- Views: 1886
- by franciskyle
Thu Mar 12, 2009 3:03 pm- Forum: Problem Solving
- Topic: Divisibility & Prime Number
- Replies: 5
- Views: 1407
To do this quicker, you could have looked at the numerator. Since it ends in 0, you automatically know that it is divisible by 1,2,5,10. That gives us 4 factors, which need each some other unique factor to multiply with to get 130 - therefore you immediately know that there are AT LEAST 8 factors. S...
- by franciskyle
Thu Mar 12, 2009 2:52 pm- Forum: Problem Solving
- Topic: Arithmetic
- Replies: 6
- Views: 1886
n < 0 & n^2 < 1/100... n < - 1/10
Multiplying both sides by -10 while dividing by n
-10 > 1/n
Therefore A
- by franciskyle
Thu Mar 12, 2009 2:02 am- Forum: Problem Solving
- Topic: Reciprocal
- Replies: 3
- Views: 1376
The absolute value for the ratios is the same, but the ratios themselves are not.
Put it into English to better understand:
A:
I have two for every one that you do not have
B:
I have two for every one that you have
- by franciskyle
Thu Mar 12, 2009 1:52 am- Forum: Problem Solving
- Topic: Can RATIO be negative?
- Replies: 4
- Views: 26360