F is true. Since rock varnish in Theil area consists of limonite, it must have penetrated down at some point in the past. Although, the snow did not melt in recent times, this does not exclude the possibility that it never melted. In fact, it must have melted sometime ago (in past) since it did not ...

Distance = 180kms Bus A takes 3 hours to cover 180 kms (go from X to Y) Bus B takes 4.5 hours to go from x to Y Now Bus A Starts from X at 11:00 AM, reaches Y at 2:00 PM, waits for 15 mins and starts to return to Point X at 2:15 PM Bus B starts from point X at 11:15Am and until 2:15PM, it covers 40*...

First Approach: Train A starts every 60/4 = 15 mins Train B starts every 60/6 = 10 mins Train C starts every 60/8 = 7.5 mins Train D starts every 60/12 = 5 mins LCM of above times = 30 Therefore after every 30 mins, all 4 trains start together. Hence D Second approch: Train A starts every 60/4 = 15 ...

# ways to pick 1 Q from Ch 1 and Ch 2 each = 3C1 = 3 # ways to pick 1 Q from Ch 3 and Ch 4 each = 6C1 = 6 %th question can be picked out of any of the remaining 14 questions (Total there were 18 qs (3+3+6+6) out of which 4 Qs have been selected so left Qs = 14) Total # of ways to make the 5 Q paper ...

ST1: X^10 + X^(-10) or {x^20 + 1}/x^10
given x is an integer greater than 1, this will never be an integer.
Hence Sufficient.

St2: X^(1/6) + X^(1/2)
if x = 64, the above becomes 2 + 8 = 10 (INTEGER)
if x = 2, the above becomes 2^1/6 + root2 (NOT an INTEGER)
Hence Insufficient

IMO A

The argument is of the strcture: Premise: If A (serious accident) THEN B (major congestion) Conclusion: If B (major congestion) THEN A (serios accident) If we analyze Opetion B, we see a similar parallel and flawed reasoning Prem: If A (nice weather), THEN B (S & D play tennis) Concl: If B (S &a...

IMO C

OA plz!!!

We know PR is the diameter. Any triangle drawn with PR as a side and 3rd point (Q) on the circumference of a circle is a right angled triangle at point Q. If we draw a perpendicular from Q on the diameter, say point T, then QT^2 = a * b Now we know QT = 2 so QT^2 = 4 St1: a = 4 Then we can find out ...