Search found 26 matches
I solved in some other way. Is my approach correct? Total fees=14000 man hrs=?? st1)100/man hr for 100 man hrs and 80/man hr for additional man hrs or fratcion of hr. therefore 100*100=10000 so 14000-10000=4000 4000/80=50 so total man hrs=150 statement 1 is SUFFICIENT ST 2) gives information only ab...
- by dhiren8182
Mon Feb 20, 2012 10:55 pm- Forum: Data Sufficiency
- Topic: ABC Consulting
- Replies: 2
- Views: 977
- by dhiren8182
Wed Feb 15, 2012 10:23 pm- Forum: Problem Solving
- Topic: Cost of Envelope
- Replies: 27
- Views: 11482
I tried to solve in some other way. Is this approach correct. Assuming total to be 120(divisible by all the fractions given in the que) pitchers non pitchers total foreign born 40 20 60 non foreign born 50 10 60 total 90 30 120 change/original=p/100 30-10/30*100=p 20/30*100=p therefore p=66.3% ANS C
- by dhiren8182
Wed Feb 15, 2012 8:16 pm- Forum: Problem Solving
- Topic: Avoiding Algebra problem
- Replies: 7
- Views: 2223
- by dhiren8182
Wed Feb 15, 2012 7:58 pm- Forum: Data Sufficiency
- Topic: DS question from OG Quant Review
- Replies: 7
- Views: 3149
- by dhiren8182
Wed Feb 15, 2012 7:56 pm- Forum: Data Sufficiency
- Topic: the value of y?
- Replies: 11
- Views: 1149
Your explanation is baffling for me. values of x=2 and -1 Substituting same to get value of y (as asked in the question ) y=1/4 x^2 STATEMENT 1:x is positive .implies value of x would be 2 so y=1/4 2^2=>1 i.e y=1 SUFFICIENT Statement 2:x and y are integers . if x=2 y=>1 if x=-1 y=>1/4 not an integer...
- by dhiren8182
Wed Feb 15, 2012 4:31 am- Forum: Data Sufficiency
- Topic: the value of y?
- Replies: 11
- Views: 1149
The way i solved it!!! Total no of ways to arrange 6 people =6! Condition: Mike and Stuart are not sitting together Anurag and Ron are not sitting together . Consider arranging Mitch and Rich in 2! ways+considering M & S as 1 group+considering A & S as 1 group . Therefore total no of ways is...
- by dhiren8182
Wed Feb 15, 2012 3:39 am- Forum: Problem Solving
- Topic: the BTG experts
- Replies: 16
- Views: 2564
Hi Anurag, I solved it in some other way. Is this right or wrong? No of stamps Kaye and Alberto had be 5x and 3x respectively. Now Kaye gives away 10 stamps so no of stamps Kaye has is 5x-10 and that Alberto has is 3x+10 So 5x-10/3x+10=7/5 =>25x-50=21x+70 =>4x=120 =>x=30 Substituting value of x in 5...
- by dhiren8182
Tue Feb 14, 2012 8:42 pm- Forum: Problem Solving
- Topic: Number of Stamps - GMAT Prep Question - Please help
- Replies: 7
- Views: 3364
Probabilty Question:2 couples and 1 person
How to solve this??? Two couples and one single person are seated at random in a row of five chairs. What is the probability that neither of the couples sits together in adjacent chairs? a)1/5 b)1/4 c)3/8 d)2/5 e)1/2 I am having problems in Probability .Especially when to choose P or choose C(Permu...
- by dhiren8182
Thu Oct 13, 2011 1:50 am- Forum: Problem Solving
- Topic: Probabilty Question:2 couples and 1 person
- Replies: 2
- Views: 948
Statistics -Pls help me to solve this problem
Q:Matt gets a $1,000 commission on a big sale. This commission alone raises his average
commission by $150. If Matt's new average commission is $400, how many
sales has Matt made?
How to Solve this problem??
- by dhiren8182
Sun Sep 18, 2011 9:04 pm- Forum: Problem Solving
- Topic: Statistics -Pls help me to solve this problem
- Replies: 7
- Views: 3685
Ratios-Please help me
Q:Matt gets a $1,000 commission on a big sale. This commission alone raises his average
commission by $150. If Matt's new average commission is $400, how many
sales has Matt made?
How to Solve this problem.
- by dhiren8182
Sun Sep 18, 2011 8:58 pm- Forum: Problem Solving
- Topic: Ratios-Please help me
- Replies: 1
- Views: 862