Good call, ssmiles08. I thought it was D until I read what you said about K being 2 or 3. I now am 100% behind ssmiles08's answer.

That's tricky. I guessed C until I read the OA. All cows are lions and all lions are goats. all cows are goats. But that does not mean all goats are cows. If there are 100 cows, then there are 100 lions and then there are 100 goats. But if there's 103 goats, then only 100 cows are goats, but there a...

I think it's A.

Haha, three different people, three different answers.

I am going to say Answer B.

I counted in my head.

10 triangles using F.

5 triangles without F.

I'm interested in seeing how to solve this in a more efficient manner.

Since I don't know the OA, I'm going to assume it's A. This is a rough one, but even I have my doubts on A. A: Everything looks right with this, but the "had remained" part makes me question if it is right, but it seems to be since the simple past tense was used for 1989 so it makes sense ...

This is how I did the problem. Case A: 150/725 (real number) Case B: 2/3 (ratio) Combined: (150 + 2x) / (725 + 3x) = 3/5 The reason for the x is because case B is a ratio and we don't know what the real number is. Now we cross multiply: 3(720 + 3x) = 5(150 + 2x) 2175 + 9x = 750 + 10x 1425 = x 2x + 3...

I think it is C. Which (referring to the plural "coolness of judgment and mutability of purpose...") were in fact natural outgrowths (plural) of it.

OA?

This is how I solved it: Class A Range = r Greatest Height = g Class B Range = s Greatest Height = h Data 1: r<s. The range for Class A is less than the range for class B. This is insufficient because we it doesn't tell us anything about the least height of the students. Data 2: g>h. The greatest he...