## Search found 354 matches

##### Difficult Math Problem #121 - Interest

A person put 1000 dollars in a bank at a compound interest 6 years ago. What percentage of the initial sum is the interest if after the first three years the accrued interest amounted to 19% of the initial sum? A) 38% B) 42% C) 19% D) 40% E) 50% from diff math problem doc, oa coming when ppl respon...

- by 800guy

Fri Apr 20, 2007 8:44 am- Forum: Problem Solving
- Topic: Difficult Math Problem #121 - Interest
- Replies:
**5** - Views:
**2705**

##### OA

OA:

a2 = k-1 ; b2 = k+1

a3= (k+1)-(k-1) = 2 ; b3 = (k+1)+(k-1) = 2k

a4 = 2k - 2 = 2(k-1) = 2(b1-a1)

- by 800guy

Fri Apr 20, 2007 8:43 am- Forum: Problem Solving
- Topic: Difficult Math Problem #120 - Sequences
- Replies:
**4** - Views:
**3890**

##### Difficult Math Problem #120 - Sequences

**Sequence A and B. a1=1, b1=k. an=b(n-1)-a(n-1) bn=b(n-1)+a(n-1). What is a4=?**

from difficult math problems doc, oa coming after people answer with questions

- by 800guy

Wed Apr 18, 2007 8:18 am- Forum: Problem Solving
- Topic: Difficult Math Problem #120 - Sequences
- Replies:
**4** - Views:
**3890**

##### OA

OA:

(x+y)30/100 = x*40/100 + y*25/100

30x + 30y = 40x + 25y

y = 2x or y/x = 2/1 or y:x = 2:1 hence x = 33 1/3%

- by 800guy

Wed Apr 18, 2007 8:15 am- Forum: Problem Solving
- Topic: Difficult Math Problem #119 - Arithmetic
- Replies:
**7** - Views:
**3278**

- by 800guy

Mon Apr 16, 2007 8:06 am- Forum: GMAT Verbal & Essays
- Topic: Verbal Strategy book
- Replies:
**22** - Views:
**33347**

##### Difficult Math Problem #119 - Arithmetic

Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ? (A) 10% (B) 33 1/3% (C) 40% (D) 50% (E) 66 2/3% from diff ma...

- by 800guy

Mon Apr 16, 2007 7:56 am- Forum: Problem Solving
- Topic: Difficult Math Problem #119 - Arithmetic
- Replies:
**7** - Views:
**3278**

##### oa

OA: Number of integers that divide 3: the range is 100-150 Relevant to this case, we take 102 - 150 (since 102 is the first to div 3) 102 = 34*3 150= 50*3, so we have 50-34+1 = 17 multiples of 3 For multiples of 5, 100=5*20 150=5*30 30-20+1 =11 Now we have a total of 27 integers, but we double count...

- by 800guy

Mon Apr 16, 2007 7:55 am- Forum: Problem Solving
- Topic: Difficult Math Problem #118 - Number Theory
- Replies:
**3** - Views:
**17329**

##### Difficult Math Problem #118 - Number Theory

**How many integers between 100 and 150, inclusive can be evenly divided by neither 3 nor 5?**

from diff math doc, ans coming after ppl respond with explanations

- by 800guy

Fri Apr 13, 2007 9:29 am- Forum: Problem Solving
- Topic: Difficult Math Problem #118 - Number Theory
- Replies:
**3** - Views:
**17329**

##### oa

oa:

Chance of drawing a blue on the first draw = 2/8, so chance of not drawing a blue on the first draw is 6/8

similarly chance of not drawing blue on second draw = 5/7

Therefore probability of not drawing blue in 2 draws = 6/8*5/7 = 15/28

- by 800guy

Fri Apr 13, 2007 9:28 am- Forum: Problem Solving
- Topic: Difficult Math Problem #117 - Probability
- Replies:
**8** - Views:
**2572**

##### Difficult Math Problem #117 - Probability

A certain deck of cards contains 2 blue cards, 2 red cards, 2 yellow cards, and 2 green cards. If two cards are randomly drawn from the deck, what is the probability that they will both are not blue? A. 15/28 B. 1/4 C. 9/16 D. 1/32 E. 1/16 oa coming after some people respond, from diff math doc

- by 800guy

Wed Apr 11, 2007 12:42 pm- Forum: Problem Solving
- Topic: Difficult Math Problem #117 - Probability
- Replies:
**8** - Views:
**2572**

##### OA:

OA:

right triangle with sides x<y<z and area of 1 => z = hypotenuse and xy/2 = 1

i.e xy = 2

If x were equal to y, we would have had xy = y^2 = 2. And y = root2

But, x<y and so y>root2.

- by 800guy

Wed Apr 11, 2007 12:41 pm- Forum: Problem Solving
- Topic: Difficult Math Problem #116 - Triangles
- Replies:
**4** - Views:
**1653**

##### Difficult Math Problem #116 - Triangles

A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y ? A. y > ROOT2 B. ROOT3/2 < y < ROOT2 C. ROOT2/3 < y < ROOT3/2 D. ROOT3/4 < y < ROOT2/3 E. y < ROOT3/4 from diff ma...

- by 800guy

Mon Apr 09, 2007 7:42 am- Forum: Problem Solving
- Topic: Difficult Math Problem #116 - Triangles
- Replies:
**4** - Views:
**1653**

##### oa

oa: there are actually 20 ways to interchange the letters, namely, the first letter could be one of 5, and the other letter could be one of 4 left. So total pairs by product rule = 20. Now, there are two cases when it wouldn’t change the name. First, keeping them all the same. Second, interchanging ...

- by 800guy

Mon Apr 09, 2007 7:41 am- Forum: Problem Solving
- Topic: Difficult Math Problem #115 - Probability
- Replies:
**5** - Views:
**3347**

##### Difficult Math Problem #115 - Probability

**My name is AJEET. But my son accidentally types the name by interchanging a pair of letters in my name. What is the probability that despite this interchange, the name remains unchanged?
a) 5%
b) 10%
c) 20%
d) 25%
e) 30%**

oa coming after some people respond w/explanations. from diff math doc

- by 800guy

Fri Apr 06, 2007 8:51 am- Forum: Problem Solving
- Topic: Difficult Math Problem #115 - Probability
- Replies:
**5** - Views:
**3347**

##### oa

oa:

out of 8 people one team can be formed in 8c2 ways.

8c2*6c2*4c2*2c2= 2520.

The answer is 105. Divide 2520 by 4! to remove the multiples ( for example: (A,B) is same as ( B,A) )

- by 800guy

Fri Apr 06, 2007 8:50 am- Forum: Problem Solving
- Topic: Difficult Math Problem #114 - Combinations
- Replies:
**12** - Views:
**2741**