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If a and b are positive integers such that a ? b and a/b are both even integers, which of the following must be an odd integer? a-b is even so both a& b are either odd or even a/b is even, possible only if both are even(considering the above case also into account) so we can say that both a & b are ...
450y =n^3 so we need a value of y which will make the expr 450y a perfect cube 450 = 3^2 * 5^2 *2 i.e none of the peime factors have the power of 3 so y must provide this i.e y should have a 3,5,& two 2's to have powers of 3 of all the prime factors in 450y in general y should be of the form 3^n*5^n...
Agree with Camitava, ans should be E 3.2xy6 If x and y each represent single digits in the decimal above, what digit does x represent? (1) When the decimal is rounded to the nearest tenth, 3.2 is the result. decimal can be 3.15 -- 3.24 INSUFF (2) When the decimal is rounded to the nearest hundredth,...
If x > 0, is x > y ? 1) 7x - 4y = 3 i.e 7x > 4y or x > 4/7*y so in this case x>y is possible, but it is also possibe that x is less than y e.g x =0.8 *y 2) 4x - 7y = 3 i.e 4x > 7y or x > 7/4*y i.e x > 7/4*y > y i.e x >y SUFF B Hi Eric/Gabriel, Is there a problem with inequality signs, whenever I put...
Many Congratulations Sam, you've demonstrated the result of being optimistic
IMO 10 2 blue 2 red 1 yellow 1 pink coz each of the 2 blue colour flowers & 2 red will make the same colour combination so basically we will have 2 possiblities 1) all 3 flowers are of diff colours i.e. 4C3 = 4ways 2) 2 flowers of the same colour & third of a diff colour i.e 3 for blue & 3 for red s...
he calcuates the dollar amount of the tip as 2 times the tens digit of the amount of his bill stmt 1: the amount of the bill was between $15 and $50 so tip can be between $2 & $10 & 15% OF 15 = 2.25 & 50 is 7.5 INSUFF stmt 2: tip was $8 so tens digit of the bill would be 4 so the amt can be between ...
Is x negative? 1. x^3(1-x^2) < 0 i.e x^3 -x^5 < 0 or x^3 < x^5 here x can be +ve like 2 & x can be -ve like -.2 INSUFF 2. x^2 - 1 < 0 or x^2 <1 i.e x <1> -1 again both -ve & +ve values are possible INSUFF Combine x^3 < x^5 & x <1> -1 so x can be -1<x<0 to satisfy both the conditions hence -ve SUFF C
Hi GMATDUD, I would solve for stmt 2 like this if y>=0, what is the value of x? B) lx-3l <y>=0 so -y will be 0 or -ve now |x-3| is an absolute value so it will be always +ve so in the given inequality the only real world case that will arise will be when y=0 as for other values of y -y will be -ve w...
Congratulations Neeraj & best of luck for ur apps.
- by samirpandeyit62
Mon Dec 10, 2007 6:10 am
- Forum: I just Beat The GMAT!
- Topic: 700 (Q-47,V-39) : A beutiful journey over..what's ahead?
- Replies: 6
- Views: 3410
Many many congratulations RI thats a fantastic score, I'm really happy for you. Now you can apply to any B-School you want & ofcourse u would be amongst the top GMAT scorers if u apply to ROSS, wish u all the best for ur apps.
IMO a good approach is to extract the common part in both the exponents & then work with the problem, In fact this step will itself present the soln
i.e 2^100 - 2^96?
2^96 ( 2^4- 1)
ans 5 C