## Search found 23 matches

@Limestone , u could have posted the OA after sometime after the question was answered. Many people were hurt and windows broken(Fragment of the sentence) (1) Many people were hurt (2) Many people were windows broken. The same thing is used in choices A and B. For this reason alone i eliminated A an...

- by junegmat221

Wed Dec 15, 2010 10:13 am- Forum: Sentence Correction
- Topic: An ellipsis question
- Replies:
**12** - Views:
**2000**

Here Its still better to minimise the usage of variables by selecting the Deepest encoded variable which is the Brother and we shall assign him a weight of B. If his weight is B, then Leo's weight would be 340-B. I tried to draw a table.But was not able to do it.Its just for a better understanding. ...

- by junegmat221

Tue Dec 14, 2010 7:59 am- Forum: Problem Solving
- Topic: Weight gain
- Replies:
**35** - Views:
**15012**

Hi.. cant we approach this question in the following fashion: The prob of it being grape=1/6 we have three boxes with 2,3, and 4 beans ... hence : Box 1: P(Grape)=1/6 P(other)=1(5/5) Box 2: same Box 3: Same Hence P=P1+P2+P3 =1/6*1+1/6*1+1/6*1 =3/6 Experts please comment whether this can also be used.

- by junegmat221

Tue Dec 14, 2010 7:19 am- Forum: Problem Solving
- Topic: Jellybean Probability
- Replies:
**30** - Views:
**18442**

(B) was necessary for developing and enforcing the principle of all juries being Please look at other statements. They needed a century of case-by-case adjudication, to (develop and enforce)implant the principle of selecting the juries from fair sections of the society. This is the intended meaning...

- by junegmat221

Tue Dec 14, 2010 12:22 am- Forum: Sentence Correction
- Topic: Although the Supreme Court ruled as long ago as 1880
- Replies:
**7** - Views:
**7587**

@Rahul, this method takes odd factors namely 2 to the power 0 , y to the power 0 (since y is odd and 2 is the only even prime) y to the power 1 z to the power 0 (since z is odd and 2 is the only even prime) z to the power 1 I thought these five would negate the Total number of factors(16) and result...

- by junegmat221

Tue Dec 14, 2010 12:08 am- Forum: Problem Solving
- Topic: challenge number properties ........ continued
- Replies:
**3** - Views:
**936**

So, we would have to consider Ella and mike to be together...which means we are left with 3! and it comes to 6... I am sorry with this explanation... Actually it should have been 4!/ (2!)= 12 ways. 2!->since we have taken Ella and Mike together... Anyway, Coming back to the question again where Ell...

- by junegmat221

Wed Dec 08, 2010 10:22 am- Forum: Problem Solving
- Topic: racing permutations
- Replies:
**7** - Views:
**1195**

What if the question actually meant this.. 2nd place Mike 1st Place Ella and 3rd place Mike 2nd place Ella and 4th place Mike 3rd Place Ella. What if i needed to find out where Ella and Mike donot finish in any other position.. other than being in (1 and 2 or 2 and 3 or 3 and 4).. In this case i wou...

- by junegmat221

Wed Dec 08, 2010 1:43 am- Forum: Problem Solving
- Topic: racing permutations
- Replies:
**7** - Views:
**1195**

@Rahul, Can u please detail us on what are the strict guidelines to be followed , When dealing with inequalities like the one above. You cannot subtract inequalities like this. It's not equation! Only thing we know from question stem and statement 1 is both (w + x) and (x + y) is less than zero. We ...

- by junegmat221

Sat Dec 04, 2010 10:47 pm- Forum: Data Sufficiency
- Topic: If w + x is < 0, is w - y > 0?
- Replies:
**5** - Views:
**1044**

8 * 12 = 96 Cubes with two color on Its FACE { ON every Edge of Cube 8 Cube Excluding Corners of Cube } @ Goyalsu, I can only visually imagine this. But it becomes harder when the cube is not 1000 in volume or if the smaller cubes are not 1cm in each of its side. It is a little bit hard in exams wh...

- by junegmat221

Sat Dec 04, 2010 10:29 pm- Forum: Data Sufficiency
- Topic: Cube Problem
- Replies:
**5** - Views:
**1998**

1 & 2 Together: w must be equal to -1 and in that case x and y can be any even integers (not necessarily same integer). Not sufficient. @ Rahul, Why should the x and y be any even integer. Infact it can be any integer. By the conditions given, 1> w^x = w^y Here w can be one, and x and y can be any ...

- by junegmat221

Sat Dec 04, 2010 6:32 am- Forum: Data Sufficiency
- Topic: If WXY does not = 0
- Replies:
**8** - Views:
**1438**

I have some difficulty understanding TestLuv explanation. I divided the set into H1,H2...H5 and W1,W2...W5... H - Husband, W- Wife and the number indicates the couple number. So if we need a community of people who dont include those in the couples together,Then our selection should be 1. From the h...

- by junegmat221

Sat Dec 04, 2010 5:51 am- Forum: Problem Solving
- Topic: Combinations 3
- Replies:
**9** - Views:
**1171**

Well for this question its best to assume . Start with N ^2 < 0.01 Equate to some number square of a number which also has integer roots. So, N^2 can be equal to -(0.04). Because N is left of 0 in the number line. Now Take square root of N which is will be equal to -(0.2) which is essentially -(2/10...

- by junegmat221

Sat Dec 04, 2010 5:37 am- Forum: Problem Solving
- Topic: GMAT Question
- Replies:
**3** - Views:
**1119**

Well, i didnt get much into the technical portions because we will be unsure as shovan did in the earlier posts. Its always to better to approach from a Practical perspective. We are given three keys namely A B C. There are three boxes D E F( D is 1$ , E is 100$, F is 1000$) Let us assume the right ...

- by junegmat221

Sat Dec 04, 2010 5:29 am- Forum: Problem Solving
- Topic: Game show
- Replies:
**32** - Views:
**13174**

Absolutely great... This is the most concise solution. But if u needed a time consuming solution , it would be this. It would surely take ur 2 mins off. Use the formula (n(n+1)(2n+1))/6 First compute for first 44 natural numbers.. Second compute for first 35 natural numbers.(In exam time if we didnt...

- by junegmat221

Sat Dec 04, 2010 3:38 am- Forum: Problem Solving
- Topic: Quick One
- Replies:
**4** - Views:
**847**

Let the Colors Be A,B,C and D. Three possibilities. 1 Color to Identify each file. - Each color to identify every file. 4 Ways. (4C1 Ways) 2 Colors to Identify each file - Here the order of the color matters. Since order matters we have to proceed with permutation. 4P2 ways= 12 ways (AB,BA, CD,DC, B...

- by junegmat221

Sat Dec 04, 2010 12:57 am- Forum: Problem Solving
- Topic: combinations /600-650
- Replies:
**5** - Views:
**1265**