## Search found 52 matches

My solution: 1. 1 - P(only one remain after 10 years) - p(no one remains after 10 years) P(no one remains after 10 years) = 0.8*0.7*0.6*0.5*0.4*0.3*0.2*0.1 P(1 remains after 10 years) = 0.2*0.7*0.6*0.5*0.4*0.3*0.2*0.1 + 0.8*0.3*0.6*0.5*0.4*0.3*0.2*0.1 + 0.8*0.7*0.4*0.5*0.4*0.3*0.2*0.1 + 0.8*0.7*0.6*...

- by akdayal

Wed Oct 27, 2010 6:35 am- Forum: Problem Solving
- Topic: Tricky PnC and probablity question
- Replies:
**11** - Views:
**4194**

1/3 is non terminating.

1/2 and 1/5 are terminating fraction,

so, b and d will decides terminating of p/q

if b > d then p/q will be terminating decimal.

if b < d then p/q will be non terminating decimal.

Hence, st 1 is not sufficient as discussed above.

st2 is sufficient

Hence B

- by akdayal

Fri Sep 03, 2010 12:09 pm- Forum: Data Sufficiency
- Topic: Terminating decimals
- Replies:
**2** - Views:
**707**

before change in january total cost T1 = f + v ----- (1) After change in jan T2 = kf + 0.95v |T2 - T1|/T1 = ?? consider stm1 T2 = 1.13f + 0.95v ------------------------------(2) can't calculate %change in total cost. st2. f = 5v ------------------------------------------(3) st2 alone is not sufficie...

- by akdayal

Fri Sep 03, 2010 11:21 am- Forum: Data Sufficiency
- Topic: FC VC
- Replies:
**2** - Views:
**804**

statement 1. a = b -1 ==> a[(a+1)^2] = (b -1)(b)^2 It depends on value of a or b so, st1 is not sufficient. Statement2. a = (b^2) - 1 ==> a(b)^2 = a(a +1) = ((b)^2 + 1)((b)^2) Again it depends on value of a or b so, st2 is also not sufficient. consider both together. a = b - 1 --- (1) a = b^2 -1 = (...

- by akdayal

Fri Sep 03, 2010 11:05 am- Forum: Data Sufficiency
- Topic: equations
- Replies:
**1** - Views:
**736**

total number of resp = 1200 = n

X = N(BF - NF - FRT)

N (Uf) + N (FRT) - N (uf and FRT) + X = n

==> 0.56n + 0.48n - 0.3n + X = n

=> n = 0.26n = 0.26 * 1200 = 312

Hence A

- by akdayal

Wed Aug 11, 2010 11:10 am- Forum: Problem Solving
- Topic: Please help ... Doubt :Venn diagrams problem
- Replies:
**3** - Views:
**982**

Ans C

Basically you have to arrange 4 Y(to rain) and 3N (not to rain)

= 7!/(4!*3!) = 35

Hence prob = 35/2^7 = 35/128

- by akdayal

Fri Jul 30, 2010 10:11 am- Forum: Problem Solving
- Topic: In Rwanda, the chance for rain
- Replies:
**7** - Views:
**4286**

f x not equal to -y, Is (x-y)/(x+y) >1 a) x>0 b) y > 0 @agganitk Are you sure above statement (a and b) are correct? If yes then Ans will be D On combining both statement x > 0 and y > 0 ==> |x - y| < x + y Always valid because both are +ve Hence (x -y) /(x + y) < 1 @selango x=-1,y=-3,x-y>x+y you c...

- by akdayal

Tue Jul 27, 2010 11:33 am- Forum: Data Sufficiency
- Topic: gmat prep question....
- Replies:
**5** - Views:
**913**

Ques : A person has 3 children with atleast one boy . Find the probability of having atleast 2 boys among children (Source : Arun Sharma , Quant Apt for CAT, Problem:14.5) I also have doubt on answer. According to question Total number of ways/events: 1B2G, 2B1G, 3B0G ( As it mentioned in question ...

- by akdayal

Sat Jul 24, 2010 1:57 pm- Forum: Problem Solving
- Topic: probability doubt : Need More explanation
- Replies:
**5** - Views:
**1745**

- by akdayal

Sat Jul 24, 2010 10:58 am- Forum: Problem Solving
- Topic: Help:Tough problem on exponential sequence
- Replies:
**5** - Views:
**814**

@adi_800 just considering case II I hope you have only problem in case II Case II : a < 0 and (a^2-1) > 0 a < 0 and a^2 > 1 a < 0 and |a| > 1 a < 0 and a > 1 or a < -1 Now the book that i m referring to mentions that It is impossible for a to be both negative and greater than 1, so we can focus only...

- by akdayal

Sat Jul 24, 2010 8:47 am- Forum: Data Sufficiency
- Topic: Inequality!!
- Replies:
**55** - Views:
**25862**

@adi_800

Yes, you are right as in question mentioned that circle is fully inscribed inside the rectangle

- by akdayal

Fri Jul 23, 2010 9:51 am- Forum: Data Sufficiency
- Topic: probability
- Replies:
**3** - Views:
**961**

If a and b are both positive integers, is (b^(a+1))-(b*a^b) odd? 1. a+(a+4)+(a-8)+(a+6)+(a-10) is odd 2. (b^3)+3(b^2)+5b+7 is odd take st1: a + (a +4) + (a -8) + (a + 6) + ( a-10) is odd ==> 5a -8 == odd ==> odd - even = odd ==> a is odd Now main question b(b^a - a^b) ------------ (1) lets say if b...

- by akdayal

Fri Jul 23, 2010 9:46 am- Forum: Data Sufficiency
- Topic: Numbers - Odd and Even
- Replies:
**3** - Views:
**807**

- by akdayal

Fri Jul 23, 2010 8:16 am- Forum: Data Sufficiency
- Topic: Numbers - Odd and Even
- Replies:
**3** - Views:
**807**

I would like to know how you would have solved this problem if this was a PS... Something like: If a point is chosen at random from the set of all possible point in a rectangle, what is the probability that point lies inside or on a circle of radius R when the radius of the circle is 2 and the cent...

- by akdayal

Fri Jul 23, 2010 8:10 am- Forum: Data Sufficiency
- Topic: probability
- Replies:
**3** - Views:
**961**

You can think reverse of albatross86's answer: The time is three hours earlier in California than in New York. Hence If it is 7:00 PM in California ==> 10:00PM in New York Game start time : 8:00 PM Game end time : 10:00 PM Hence game last for 2 hrs. Logic is that you have to convert in one timezone....

- by akdayal

Mon Jul 12, 2010 10:46 am- Forum: GMAT Math
- Topic: New York at 8:00 p.m.
- Replies:
**3** - Views:
**993**