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After some quick search in wikipedia This is what I found: Sum of all even numbers up to n = N(N+1) where N is the number of consecutive even numbers So: 79*80=N(N+1) therefore N=79 the last term of the sequence the nth number value is expressed as n(N)=a+(N-1)*d where a = 1st term here 2 and d = in...
- by liciniudragos
Mon Jan 25, 2010 4:50 am- Forum: Problem Solving
- Topic: Difficult Math Question #1
- Replies: 30
- Views: 26942