Search found 46 matches

by Tame the CAT

Tue May 08, 2007 6:56 pm
Forum: Problem Solving
Topic: exponents
Replies: 5
Views: 2144

The cost from increases by 5 cents per year so the setup is pretty easy

10x+10(x+5)+10(x+10)+10(x+15)+10(x+20) = 3500

50x+500 = 3500

x=60 <---- cost in 1998

so A must be the answer.

by Tame the CAT

Mon May 07, 2007 6:55 pm
Forum: Problem Solving
Topic: stamp question
Replies: 4
Views: 2351

Pretty Tough Question - Need some help

A certain league has four divisions. The respective divisions had 9, 10, 11, and 12 teams qualify for the playoffs. Each division held its own double-elimination tournament -- where a team is eliminated from the tournament upon losing two games -- in order to determine its champion. The four divisio...

by Tame the CAT

Mon May 07, 2007 11:52 am
Forum: Problem Solving
Topic: Pretty Tough Question - Need some help
Replies: 1
Views: 1361

For an equilateral triangle always remember that the Area of the Incircle = 1/12*pie*(a^2) Likewise for an equilateral triangle the Area of the Circumcircle = 1/3*pie*(a^2); Where a is the side of the triangle. Hence in this case the area would be 1/12*pie*10^2 =25pie/3 Do you want additional help ...

by Tame the CAT

Sun May 06, 2007 6:16 pm
Forum: Problem Solving
Topic: prep question
Replies: 3
Views: 1762

284 rounds down (to the nearest 10) to 280, not 290

The range of miles per gallon would be

285/12.4 (the smallest possible number) to . . .

294/11.5 (the largest possible number

What are the choices??

by Tame the CAT

Sun May 06, 2007 6:05 pm
Forum: Problem Solving
Topic: seemingly simple rounding question
Replies: 4
Views: 2881

sorry.

if r = 100*SQROOT{[(v+q)/p]-1}

by Tame the CAT

Fri Apr 27, 2007 8:11 am
Forum: Problem Solving
Topic: Interest - Very Difficult!!
Replies: 2
Views: 1812

Probability

John and Peter are among the nine players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes John and Peter?

A 1/9
B 1/6
C 2/9
D 5/18
E 1/3

by Tame the CAT

Fri Apr 27, 2007 5:16 am
Forum: Problem Solving
Topic: Probability
Replies: 4
Views: 2328

Interest - Very Difficult!!

An investor purchased a share of non-dividend-paying stock for p dollars on Monday. For a certain number of days, the value of the share increased by r percent per day. After this period of constant increase, the value of the share decreased the next day by q dollars and the investor decided to sell...

by Tame the CAT

Fri Apr 27, 2007 4:40 am
Forum: Problem Solving
Topic: Interest - Very Difficult!!
Replies: 2
Views: 1812

I missed the at least part!! dammit. I'll post the solutions when I get home.

by Tame the CAT

Fri Apr 27, 2007 2:31 am
Forum: Problem Solving
Topic: Very tough Probability Question
Replies: 6
Views: 4309

This problem is insane!!

Not sure how to attack this problem Eighty percent of the lights at Hotel California are on at 8 p.m. a certain evening. However, forty percent of the lights that are supposed to be off are actually on and ten percent of the lights that are supposed to be on are actually off. What percent of the lig...

by Tame the CAT

Thu Apr 26, 2007 5:35 pm
Forum: Problem Solving
Topic: This problem is insane!!
Replies: 5
Views: 2102

This is what I did

Numerator: 10!/(8!2!)*5!/4! = 225

Denominator: 15!/(12!*3!) = 455

or 45/91

by Tame the CAT

Thu Apr 26, 2007 5:29 pm
Forum: Problem Solving
Topic: Very tough Probability Question
Replies: 6
Views: 4309

Here is the official solution. Sorry, I should have posted it. Someone pm-ed me. I should be more considerate for the others studying. Also look at the attachment ----------- According to the question, the ratio of the lengths of arc AC to arc AB to arc BC is 6: 2: 1. An inscribed angle cuts off an ...

by Tame the CAT

Thu Apr 26, 2007 1:03 pm
Forum: Problem Solving
Topic: Geometry
Replies: 11
Views: 4924

Very tough Probability Question

If a jury of 12 people is to be selected randomly from a pool of 15 potential jurors, and the jury pool consists of 2/3 men and 1/3 women, what is the probability that the jury will comprise at least 2/3 men?

A 24/91

B 45/91

C 2/3

D 67/91

E 84/91

by Tame the CAT

Thu Apr 26, 2007 1:00 pm
Forum: Problem Solving
Topic: Very tough Probability Question
Replies: 6
Views: 4309

nevermind. I got it. I feel like an idiot!!

by Tame the CAT

Wed Apr 25, 2007 3:31 pm
Forum: Problem Solving
Topic: Geometry
Replies: 11
Views: 4924

Geometry

The length of minor arc AB is twice the length of minor arc BC and the length of minor arc AC is three times the length of minor arc AB. What is the measure of angle BCA? 20 40 60 80 120 I don't know the answer yet, but whatever I'm getting isn't one of the answer choices. BTW. Triangle ABC is inscr...

by Tame the CAT

Wed Apr 25, 2007 3:21 pm
Forum: Problem Solving
Topic: Geometry
Replies: 11
Views: 4924