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Re: Geometry

Since you know AG = 3CE and DG = 3DE ...eq(1), Now the area of the top most triangle(CDE) =1/2(EC x DE) = 42 ...eq(2) (given) And Now, consider the area of the entire triangle(ADG) = 1/2(AG x DG) = 1/2(3EC x 3DE)-------- replace the values using (eq(1)) = 9/2(EC x DE) = 9(1/2(EC x DE)) ---eq(3)--- ...

by harrycharlesop

Fri Oct 09, 2020 9:46 pm
Forum: GMAT Math
Topic: Geometry
Replies: 5
Views: 21302