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Re: Geometry
Since you know AG = 3CE and DG = 3DE ...eq(1), Now the area of the top most triangle(CDE) =1/2(EC x DE) = 42 ...eq(2) (given) And Now, consider the area of the entire triangle(ADG) = 1/2(AG x DG) = 1/2(3EC x 3DE)-------- replace the values using (eq(1)) = 9/2(EC x DE) = 9(1/2(EC x DE)) ---eq(3)--- ...
- by harrycharlesop
Fri Oct 09, 2020 9:46 pm- Forum: GMAT Math
- Topic: Geometry
- Replies: 5
- Views: 26568