## Search found 15 matches

#### A loan of $10,000 has an annual interest rate of 8%, compounded quarterly. What will be the total due (principal + inter ###### Problem Solving ##### Re: A loan of$10,000 has an annual interest rate of 8%, compounded quarterly. What will be the total due (principal + i

Since, annual interest is $$8\%$$ , interest per quarter is $$2\%$$

Number of payment periods = Number of quarters in 12 months = 4

Amount due = $$P\ \cdot\ \left(1.02\right)^4\ =\ 10000\ \cdot\ \left(1.0824\right)\ =\ 10824$$ D

#### Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Chadi

##### Re: Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Cha

Speed of Nicky = 3m/s

Speed by which Chadi catches up with Nicky = 5m/s - 3m/s = 2m/s

Distance that Nicky is initially ahead = 36m

So time taken to catch up = $$\frac{36}{2}\ =\ 18$$ B

#### Cost is expressed by the formula $$tb^4.$$ If $$b$$ is doubled and $$t$$ remains the same, the new cost is how many time

##### Re: Cost is expressed by the formula $$tb^4.$$ If $$b$$ is doubled and $$t$$ remains the same, the new cost is how many

Let $$t'$$ and $$b'$$ be the new parameters.

So,

$$t'\ =\ t$$ and $$b'\ =\ 2\ \cdot\ b$$

New cost = $$t'\ \cdot\ b'^4\ =\ t\cdot\left(2\cdot b\right)^4\ =\ t\cdot16\cdot b^4\ =\ 16tb^4$$

So, the answer is 16 E

#### A 400 milliliter solution is 20% alcohol by volume. If 100 milliliters of water is added, what is the new concentration

##### Re: A 400 milliliter solution is 20% alcohol by volume. If 100 milliliters of water is added, what is the new concentrat

Initially, the solution is $$20\%$$ alcohol by volume. This means that out of 400 ml of the solution, Volume of alcohol = $$\frac{20}{100}\ \cdot\ 400\ =\ 80$$ Since, we add 100ml water to this solution, the volume of solution becomes 500ml, but the volume of alcohol does not change. So, now the con...

#### The average (arithmetic mean) of 11 numbers is 10. When one number is eliminated, the average of the remaining numbers

##### Re: The average (arithmetic mean) of 11 numbers is 10. When one number is eliminated, the average of the remaining numbe

We know that if mean of $$n$$ numbers is $$M$$ , then sum of the numbers is $$n\ \cdot\ M$$

So, sum of the 11 numbers is $$11\ \cdot\ 10\ =\ 110$$

After removing one number, sum of remaining numbers is $$9.3\ \cdot\ 10\ =\ 93$$

So the removed number is $$110\ -\ 93\ =\ 17$$ D

#### An empty bucket is filled with paint at a constant rate, and after 6 minutes the bucket is filled to 3/10 of its

##### Re: An empty bucket is filled with paint at a constant rate, and after 6 minutes the bucket is filled to 3/10 of its

Since, $$\frac{3}{10}$$ of the bucket took 6 minutes to fill.

Therefore, total time to fill the bucket is $$\frac{1}{\frac{3}{10}}\cdot\ 6\ =\ \frac{10}{3}\ \cdot\ 6\ =\ 20$$ minutes.

So remaining time to fill the bucket = $$20\ -\ 6\ =\ 14$$

#### The price of a model $$M$$ camera is $209 and the price of a special lens is$69. When the camera and lens are purchased

##### Re: The price of a model $$M$$ camera is $209 and the price of a special lens is$69. When the camera and lens are purch

Cost of Camera = $$209$$
Cost of Lens = $$69$$
Sum of Costs = $$209\ +\ 69\ =\ 278$$
Retail price = $$239$$
Money Saved = $$278\ -\ 239\ =\ 39$$

Therefore, money saved as percent of total amount = $$\frac{39}{278}\cdot100=\ \sim14\%$$

#### In the coordinate plane, one of the vertices of a square is the point $$(-3, -4).$$ If the diagonals of that square

##### Re: In the coordinate plane, one of the vertices of a square is the point $$(-3, -4).$$ If the diagonals of that square

Let the length of the side of the square be s. Note that diagonals of a square intersect at the center of the square. Therefore, by Pythagoras theorem (s/2) $$\left(\frac{s}{2}\right)^2\ +\ \left(\frac{s}{2}\right)^2$$ = square of distance between vertex and center. So \left(\frac{s}{2}\right)^2\ ...

#### When positive integer $$n$$ is divided by 13, the remainder is 2. When $$n$$ is divided by 8, the remainder is 5. How

##### Re: When positive integer $$n$$ is divided by 13, the remainder is 2. When $$n$$ is divided by 8, the remainder is 5. Ho

Since there are not many values that give remainder 2 with 13 under 180, we can evaluate them individually.

15 -> 7
28 -> 4
41 -> 1
54 -> 6
67 -> 3
80 -> 0
93 -> 5
106 -> 2
119 -> 7
132 -> 4
145 -> 1
158 -> 6
171 -> 3

Hence there is only 1 value (93) B

#### If x is an integer greater than 2, the function f(x)

##### Re: If x is an integer greater than 2, the function f(x)

Let us evaluate f(51) in terms of f(50).

Since f(51) = 2 * 4 * 6 * ... * 50
And f(50) = 2 * 4 * 6 * ... * 50

Therefore f(51) = f(50)

So f(51) - f(50) = f(50) - f(50) = 0 (E)

Sat May 30, 2020 11:04 pm
Forum: GMAT Math
Topic: If x is an integer greater than 2, the function f(x)
Replies: 5
Views: 11514

#### Quant- Numbers Problem

##### Re: Quant- Numbers Problem

Let us try it for all n from -20 to 20. We can only choose such n that 20 - n is divisible by 4, since m is also an integer. Since 20 is divisible by 4, n must also be divisible by 4.

So values would be -20, -16, -12, -8, -4, 0, 4, 8, 12, 16, 20 => 11 values in total.