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In the figure below AB=BC=CD. If the area of the Traingle CDE is 42,what is the area of the triangle ADG? --------- similar triangle sides of CDE are 1/3 of the Side of ADG. 9 X Area of triangle CDE = area of Triangle ADG Area of Triangle ADG =9 X 42 Area of Triangle ADG =378

by oabpyhfv

Sat Jul 20, 2019 12:25 am
Forum: GMAT Math
Topic: Data sufficiency
Replies: 3
Views: 3757

Since you know AG = 3CE and DG = 3DE ...eq(1), Now the area of the top most triangle(CDE) =1/2(EC x DE) = 42 ...eq(2) (given) And Now, consider the area of the entire triangle(ADG) = 1/2(AG x DG) = 1/2(3EC x 3DE)-------- replace the values using (eq(1)) = 9/2(EC x DE) = 9(1/2(EC x DE)) ---eq(3)--- i...

by oabpyhfv

Sat Jul 20, 2019 12:22 am
Forum: GMAT Math
Topic: Mixture replacement Problems:How to solve effectively and q
Replies: 7
Views: 5973