Hi man,
Work problems --> ratios

One machine takes X hours to finishh the task and the other one takes 3/4*X to finish the same task. Together, they finish it in 6 hours so we can write:
1 / X + 1 /( (3/4)*X ) = 1/6

Solve this equation and you get X=14

Yeah guys that is Q48, not Q28
Thanks all of you for your messages, I take a break for the moment.

About "rather than", do we have to use "as" or not ?

In this case, you cannot chose y=1 or y=-6 You can see that for y=1, y^2 is different from 36 for y=-6, y^2- 7y + 6 is different from 0 But with y=6 we have y^2 = 36 and y^2- 7y + 6 = 0 What you look is a solution which suits both statements, your solution cannot contradict with one equation but be ...

I am ok for the time but it is important to look at what the question asks be it a DS or not! It is possible that two sets respect all conditions but have a different number of primes. Anyway, it's true that timing is short for this one if you do not find the spirit as we do not. I think I would hav...

I don't follow how you state that 1) is right for example. Did I miss something in the question? 6 to 18 We have 3 multiples of 6 and 2 multiples of 5 which are also multiples of either 2 or 3. We have primes: 7,11,13,17 --> 4 primes 42 to 54 We have 3 multiples of 6 and 2 multiples of 5 which are a...

There is no special way for this question.
As Bourne told there is nothing to do with statement 1 alone given there is x and nothing simplifies.
Statement 2
Result is either -8 or 11

With statement 1 and 2 you need to chose a positive one number so it's 11

It is clear that statement one is the most complicated. y>2x must be true? Let's try to find a counter-example, if we cannot so it must be true. In your example, you want Norman to earn more than twice as much as he did last week. If we chose x=10 and y=18 we have y<2x Revenue with 10: 20 + 6*6 + 4*...