## Search found 28 matches

gmattarget700 wrote:hey Komal...this seems excellent tool...

BUT not working for me... as click to Start doesnt work

can anyone comment on what could be wrong? Seems everyone is njoying the tool except me...I have Win XP

thanks

You need to enable macros in excel to get this thing to work.

- by hrishikesh05

Tue Feb 02, 2010 7:19 am- Forum: GMAT Strategy
- Topic: I Just Downloaded This Amazing Timed-Test-Grid !!!
- Replies:
**17** - Views:
**5608**

I share a very similar story to you.

I too got 730 and 740 on my GMAT Prep exams

In the real exam i got 650. Completely shattered. But i guess i am going to give it again after reading this post.

Thanks Stacy and good luck to you 700plus for your next attmept

- by hrishikesh05

Wed Apr 01, 2009 10:28 am- Forum: I just Beat The GMAT!
- Topic: From ~740 on practice exams to 570 on real exam
- Replies:
**29** - Views:
**7456**

Statement 2 is sufficient Let the total cost for the week be x the cost per person is x/3 When the new friend joins the total cost remains the same but the cost per person comes down and becomes x/4 the savings made by the initial friends => x/3 - x/4 = 15 on solving we get the value of x = 180 ther...

- by hrishikesh05

Tue Mar 31, 2009 12:17 am- Forum: Data Sufficiency
- Topic: three friends rents a car
- Replies:
**2** - Views:
**4961**

Zero is divisible by all numbers

Zero is neither negative nor positive

The question states that x is a positive number and therefore it is not zero

In Statement 2

Zero is not an option and all the other numbers suffice

IMO B

- by hrishikesh05

Tue Mar 31, 2009 12:03 am- Forum: Data Sufficiency
- Topic: MGMAT 700-800
- Replies:
**21** - Views:
**3277**

- by hrishikesh05

Sat Mar 28, 2009 9:07 pm- Forum: Data Sufficiency
- Topic: xy-plane
- Replies:
**1** - Views:
**685**

##### Re: Second-Degree Equations

BlindVision wrote:if k NOT EQUAL 0 and k - (3 - 2k^2 / k) = x/k, then x =

A) -3 - k^2

B) k^2 - 3

C) 3k^2 - 3

D) k - 3 - 2k^2

E) k - 3 + 2k^2

OA = C

Please put the brackets in the correct place. :roll:

- by hrishikesh05

Sat Mar 28, 2009 7:22 am- Forum: Problem Solving
- Topic: Second-Degree Equations
- Replies:
**9** - Views:
**2083**

The answer is not B

The answer is C

The questions ask how much time did it take to cover the entire distance which is the 12 + 105 = 117 mins

You guys are forgetting to add the 12 mins covered at 39 mph

- by hrishikesh05

Wed Mar 25, 2009 7:56 am- Forum: Problem Solving
- Topic: 20 mile course
- Replies:
**10** - Views:
**1241**

- by hrishikesh05

Mon Mar 16, 2009 8:37 am- Forum: Critical Reasoning
- Topic: Titan Tax Relief
- Replies:
**4** - Views:
**1189**

if we look at the product of the first 30 positive integers we get 5 as a factor seven times so IMO statement 1 is sufficient

and the answer should be A

- by hrishikesh05

Mon Feb 09, 2009 6:57 am- Forum: Data Sufficiency
- Topic: GMATPREP nbr properties
- Replies:
**7** - Views:
**1357**

if we look at the product of the first 30 positive integers we get 5 as a factor seven times so IMO statement 1 is sufficient

and the answer should be A

- by hrishikesh05

Mon Feb 09, 2009 6:56 am- Forum: Data Sufficiency
- Topic: GMATPREP nbr properties
- Replies:
**7** - Views:
**1357**

if we look at the product of the first 30 positive integers we get 5 as a factor seven times so IMO statement 1 is sufficient

and the answer should be A

- by hrishikesh05

Mon Feb 09, 2009 6:54 am- Forum: Data Sufficiency
- Topic: GMATPREP nbr properties
- Replies:
**7** - Views:
**1357**

Y can also be equal to zero

2/y + 4/y = 3

2y + 4y = 3y^2

6y = 3y^2

2y=y^2

y^2 - 2y = 0

y(y-2)=0

y= 2 or 0

- by hrishikesh05

Fri Feb 06, 2009 1:47 am- Forum: Problem Solving
- Topic: How do you solve
- Replies:
**3** - Views:
**884**

- by hrishikesh05

Fri Feb 06, 2009 1:30 am- Forum: Problem Solving
- Topic: Mixture problem, whats the best approach?? GMAT Prep
- Replies:
**6** - Views:
**1808**

- by hrishikesh05

Tue Feb 03, 2009 10:04 pm- Forum: Data Sufficiency
- Topic: Gmat Prep - integer
- Replies:
**5** - Views:
**1157**

between 1 to 100 there are

50 numbers divisible by 2 (100/2)

33 numbers divisible by 3 (100/3)

That gives a total of 83 numbers

However there are numbers which area also divisible by 2 and 3 i.e. by 6.

16 numbers divisible by 6 (100/6)

Total numbers = 50+33-16 = 67

Answer = 100- 67 = 33

- by hrishikesh05

Tue Feb 03, 2009 9:00 am- Forum: Problem Solving
- Topic: numbers between 1-100
- Replies:
**9** - Views:
**64137**